Answer:
CH3CH3CH2CH3
Explanation:
Octane is a non-polar compound. It is a hydrocarbon with 8-carbon length along its chain.
It belongs to a special group of hydrocarbons called alkanes.
What makes a substance soluble in another?
It is a common phrase that "like dissolves like". This is applicable to solubility of substances in another.
- A polar solvent will freely and easily dissolve a polar solute. For example, water and salt.
- A non-polar solvent will also dissolve a non-polar solute. This case, hydrocarbons will dissolve themselves.
- The first option is a butane, a 4-carbon length hydrocarbon which will be dissolved in octane.
- Both compounds are non-polar.
Answer:
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1.062 mol/kg.
<em>Step 1</em>. Write the balanced equation for the neutralization.
MM = 204.22 40.00
KHC8H4O4 + NaOH → KNaC8H4O4 + H2O
<em>Step 2</em>. Calculate the moles of potassium hydrogen phthalate (KHP)
Moles of KHP = 824 mg KHP × (1 mmol KHP/204.22 mg KHP)
= 4.035 mmol KHP
<em>Step 3</em>. Calculate the moles of NaOH
Moles of NaOH = 4.035 mmol KHP × (1 mmol NaOH/(1 mmol KHP)
= 4.035 mmol NaOH
<em>Step 4</em>. Calculate the mass of the NaOH
Mass of NaOH = 4.035 mmol NaOH × (40.00 mg NaOH/1 mmol NaOH)
= 161 mg NaOH
<em>Step 5</em>. Calculate the mass of the water
Mass of water = mass of solution – mass of NaOH = 38.134 g - 0.161 g
= 37.973 g
<em>Step 6</em>. Calculate the molal concentration of the NaOH
<em>b</em> = moles of NaOH/kg of water = 0.040 35 mol/0.037 973 kg = 1.062 mol/kg
Answer:
Solution A is correct.
Explanation:
Strong acids or bases are assumed to dissociate completely when in a aqueous solution.
Answer:
The volume is 10,92 L
Explanation:
We use the formula PV=nRT:
V= (nRT)/P
V= (0,500 mol x 0,082 l atm/K mol x 799 K)/3,00 atm
<em>V= 10,91966667 L</em>