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2 years ago

Label the parts of the respiratory system.

Chemistry

1 answer:

Evgesh-ka [11]2 years ago

8 0

Answer:

1. Nose

2. Mouth

3. Larynx

4. Lung

5. RIght Bronchi

6. Diaphragm

7. Pharynx

8. Trachea

9. Left Bronchi

10. Bronchioles

11. Avoli

Explanation:

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In a chemical reaction,_______________are the substances present after the reaction.

dsp73

Answer:

In a chemical reaction, <u>products</u> are the substances present after the reaction

8 0

2 years ago

Read 2 more answers

A piece of silver releases 202.8 J of heat while cooling 65.0 °C. What is the mass of the sample? Silver has a specific heat of

KiRa [710]

Answer: 13 grams

Explanation:

The quantity of heat energy (Q) released from a heated substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since,

Q = 202.8 Joules

Mass of silver = ?

C = 0.240 J/g °C.

Φ = 65°C

Then, Q = MCΦ

202.8J = M x 0.240 J/g °C x 65°C

202.8J = M x 15.6 J/g

M = (202.8J / 15.6 J/g)

M = 13 g

Thus, the mass of silver is 13 grams

7 0

3 years ago

You put scruffy can run up to 2 meters/sec on his fastest days scruffy has a mass of 8 KG what is his maximum kinetic energy on

ale4655 [162]

Answer:

E = 16 J

Explanation:

We have,

You put scruffy can run up to 2 m/s on his fastest days scruffy has a mass of 8 kg

It is required to find the maximum kinetic energy on his fastest days. If v is the velocity, then kinetic energy is given by :

$E=\dfrac{1}{2}mv^2$

Plugging all the values,

$E=\dfrac{1}{2}\times 8\times 2^2 \\\\E=16\ J$

So, the maximum kinetic energy on his fastest day is 16 J.

6 0

3 years ago

The reaction between nitrogen dioxide and carbon monoxide is NO2(g)+CO(g)→NO(g)+CO2(g)NO2(g)+CO(g)→NO(g)+CO2(g) The rate constan

Alex17521 [72]

Answer : The rate constant at 525 K is, $0.0606M^{-1}s^{-1}$

Explanation :

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

or,

$\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_1$ = rate constant at $701K$ = $2.57M^{-1}s^{-1}$

$K_2$ = rate constant at $525K$ = ?

$Ea$ = activation energy for the reaction = $1.5\times 10^2kJ/mol=1.5\times 10^5J/mol$

R = gas constant = 8.314 J/mole.K

$T_1$ = initial temperature = 701 K

$T_2$ = final temperature = 525 K

Now put all the given values in this formula, we get:

$\log (\frac{K_2}{2.57M^{-1}s^{-1}})=\frac{1.5\times 10^5J/mol}{2.303\times 8.314J/mole.K}[\frac{1}{701K}-\frac{1}{525K}]$

$K_2=0.0606M^{-1}s^{-1}$

Therefore, the rate constant at 525 K is, $0.0606M^{-1}s^{-1}$

8 0

2 years ago

Why you cannot add 0.3 moles of calcium fluoride directly to 1L of water to make a 0.3 M

Semenov [28]

Answer:

Because it's not soluble in water, need to be heated acidic solution

Explanation:

Calcium Fluoride Formula: CaF2 Comprises of Ca2+ and F−

H2O = Water H+ O2- OH-

Insoluble in water

In order to dissolve a salt, you have to break apart the ions and hydrate them via a solvent.

Need to read

HSAB concept( Pearson acid-base concept) is an initialism for "hard and soft (Lewis) acids and bases"

So F- is a Halogen which is a Hard Base

And OH- is a Hard base as well

And H- is a soft base

So soft acids react best with soft bases and hard acids react best with hard bases.

Bases don't react with other bases.

4 0

3 years ago