Part A. To solve for the distance travelled during the
interval, all we have to do is to plug in values of t = 3 and t = 3.5 in the
equation and the difference would be the answer:
when t = 3: s = 16 (3)^2 = 144 m
when t = 3.5: s = 16 (3.5)^2 = 196 m
Therefore the distance travelled within the interval is:
196 m – 144 m = 52 m
<span>Part B. The velocity is calculated by taking the 1st
derivative of the equation. v = ds / dt</span>
s = 16 t^2
ds / dt = 32 t = v
when t = 3: v = 32 (3) = 96 m / s
when t = 3.5: v = 32 (3.5) = 112 m / s
Therefore the average velocity is:
(96 + 112) /2 = 104 m / s
Part C. We can still use the formula v = 32 t and plug in
the value of t = 3
v = 32 t = 32 (3)
v = 96 m / s
<span> </span>
The first question would be distance from the start, as it is steadily going up as time goes on.
The second question would be distance from the end, as it is steadily going down as time goes on.
The third question would be speed, as the speed is staying stable as shown by the straight lines seen within the distance from start/end graphs being linear lines.
John can make 28 pizzas in 4 days (hope this helped)
Note:
sin(-θ) = -sinθ
sin(-15°) = -sin15° Use a calculator
sin(-15°) = -sin15° = -0.2588
sin(-15°) = -0.2588
Answer:
67
Step-by-step explanation:
To find exterior angles you add non-adjacent interior angles.