What is the factored equation for f(x)=x+x-6

Find the equation of the line.<br> Use exact numbers.

expeople1 [14]

Answer:

y=2/3x+4

Step-by-step explanation:

rise 2

run 3

y-intercept 4

7 0

2 years ago

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Ivan and Kate live 40 miles apart. Ivan leaves his house at 8:00 a.m.

Triss [41]

Answer: Time at which the meet = 10:17:24 am

Step-by-step explanation: Speed of Ivan = 12 mph

Speed of Kate = 16 mph

Total distance traveled = Initial separation = 40 miles

Ivan leaves his house at 8:00 a.m and Kate leaves her house at 9:30 a.m

If t is the time of catch up after Ivan starting, time taken by Kate is t - 1.5,

We have

Distance = Speed x Time

Total distance traveled = Distance traveled by Kate + Distance traveled by Ivan

40 = t x 12 + (t-1.5) x 16

40 = 28t - 24

28t = 64

t = 2.29 hours

So after 2.29 hours of Ivan's starting they meet,

Time = 8:00 am + 2.29 hours = 10:00 am + 0.29 x 60 minutes = 10:17am + 0.4 x 60 seconds = 10:17:24 am

Time at which the meet = 10:17:24 am

6 0

2 years ago

As of July 1, 2014, the population of India was about 1,267,000,000. How can you write this number in scientific notation?

skelet666 [1.2K]

Answer:

1 I think its 1.267000000

Step-by-step explanation:

4 0

3 years ago

What does 4 + 5 equal

Svet_ta [14]

Answer:

9

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Find a cubic function with the given zeros.

Fed [463]

Answer:

The correct option is D) $f(x) = x^3 + 2x^2 - 2x - 4$ .

Step-by-step explanation:

Consider the provided cubic function.

We need to find the equation having zeros: Square root of two, negative Square root of two, and -2.

A "zero" of a given function is an input value that produces an output of 0.

Substitute the value of zeros in the provided options to check.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x + 4$ .

$f(x) = x^3 + 2x^2 - 2x + 4\\f(x) = (-2)^3 + 2(-2)^2 - 2(-2) + 4\\f(x) =-8 + 2(4)+4 + 4\\f(x) =8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 + 2x - 4$ .

$f(x) = x^3 + 2x^2 + 2x - 4\\f(x) = (-2)^3 + 2(-2)^2 + 2(-2) - 4\\f(x) =-8+2(4)-4-4\\f(x) =-8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 - 2x^2 - 2x - 4$ .

$f(x) = x^3 - 2x^2 - 2x - 4\\f(x) = (-2)^3 - 2(-2)^2 - 2(-2) - 4\\f(x) =-8-8+4-4\\f(x) =-16$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-2)^3+2(-2)^2 - 2(-2) - 4\\f(x) =-8+8+4-4\\f(x) =0$

Now check for other roots as well.

Substitute x=√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (\sqrt{2})^3+2(\sqrt{2})^2 - 2(\sqrt{2}) - 4\\f(x) =2\sqrt{2}+4-2\sqrt{2}-4\\f(x) =0$

Substitute x=-√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-\sqrt{2})^3+2(-\sqrt{2})^2 - 2(-\sqrt{2}) - 4\\f(x) =-2\sqrt{2}+4+2\sqrt{2}-4\\f(x) =0$

Therefore, the option is correct.

8 0

3 years ago