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3 years ago

Add. write each sum in simplest form 2 4/5 + 4 1/10

2 answers:

7 0

Answer: 6 9/10

First make 4/5 to 8/10 by making common denominator which is times 2 and multiply 4 by 2 for numerator. Now just add. 2 8/10 + 4 1/10. You first add 2+4=6. Then, add 8/10+1/10=9/10. Lastly, just put them together which is 6 9/10. That is the simplest form.

PSYCHO15rus [73]3 years ago

6 0

Ok I almost have the answer. Do you want me to explain how I did it?

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Help! How would I solve this trig identity?

NeTakaya

Using simpler trigonometric identities, the given identity was proven below.

<h3>How to solve the trigonometric identity?</h3>

Remember that:

$sec(x) = \frac{1}{cos(x)} \\\\tan(x) = \frac{sin(x)}{cos(x)}$

Then the identity can be rewritten as:

$sec^4(x) - sen^2(x) = tan^4(x) + tan^2(x)\\\\\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)} = \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)} \\\\$

Now we can multiply both sides by cos⁴(x) to get:

$\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)} = \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)} \\\\\\\\cos^4(x)*(\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}) = cos^4(x)*( \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)})\\\\1 - cos^2(x) = sin^4(x) + cos^2(x)*sin^2(x)\\\\1 - cos^2(x) = sin^2(x)*sin^2(x) + cos^2(x)*sin^2(x)$

Now we can use the identity:

sin²(x) + cos²(x) = 1

$1 - cos^2(x) = sin^2(x)*(sin^2(x) + cos^2(x)) = sin^2(x)\\\\1 = sin^2(x) + cos^2(x) = 1$

Thus, the identity was proven.

If you want to learn more about trigonometric identities:

brainly.com/question/7331447

#SPJ1

7 0

1 year ago

Help please I only have 10 minutes TT

dsp73

1. 5:15 = 1/3
scale factor is 1/3going from bigger to smaller

2. 2/8 = 1/4

14 x 1/4 = 3.5

X = 3.5

3 0

2 years ago

PLEASE ANSWER ASASP FOR BRAINLEST!!!!!!!!!!!!!!

stealth61 [152]

Answer:

32 units²

Step-by-step explanation:

this shape is a trapezoid with a height of 4 and bases that are 4 and 12 units in length

formula is: 1/2(height) x (sum of bases)

A = 1/2(4)(4 + 12)

A = 2(16)

A = 32

7 0

3 years ago

Read 2 more answers

What is the reminder when (3x^3-2x^2+4x-3) is divided by (x^2+3x+3)

NARA [144]

(For full answer you might have to go to the comments)

Answer: 28x+30

Explanation: we divide (3x^3-2x^2+4x-3) by (x^2+3x+3) Using long division
3x-11
___________________
(x^2+3x+3) 3x^3-2x^2+4x-3

-(3x^3+9x^2+9x)
__________________

-11x^2-5x-3

-(-11x^2-33x-33)
____________
28x+30

So our remainder will be 28x+30

5 0

3 years ago

According to Okun's law, if the unemployment rate goes from 5% to 3%, what will be the effect on the GDP?

olga2289 [7]

Answer:

D. It will increase by 1%.

Step-by-step explanation:

Given

$u_1 = 5\%$ --- initial rate