To start this question, we should know what is the atomic number of cobalt. The atomic number (the number of protons) of Cobalt is Z =27.
Now, we know that a Cobalt 60 isotope means an isotope of Cobalt whose Atomic Mass is 60.
Thus, in a Cobalt 60 isotope, the number of neutrons in the nucleus are

From the question we know that the given nuclear mass is 59.933820 u.
Now, the mass defect of Cobalt 60 can be easily calculated by adding the masses of the protons and the neutrons as per our calculations and subtracting the given nuclear mass from it.
Thus,
Mass Defect = (Number of Protons Mass of Proton given in the question) + (Number of Neutrons Mass of Neutron given in the question)-59.933820 u

Thus, the required Mass Defect is 0.5634u.
In eV, the Mass Defect is 
to translate a graph up you need to add the amount you want to move it to the end of the equation, not to the variable.
The answer would be y = sin x + π
Area 1 = 175.84
area 2 = 156.30
area 1: A=(pi)r^2 x 140/360
in this case we would use the degree of the entire circle and the degree of the sector since it is not given.
area 2: A=(pi)r^2 x 280/360
in this case we would use the degree of the entire circle and the degree of the sector since it is not given.
Answer:
x = 32
Step-by-step explanation:
The longest side is double the length of the shortest side, so x is 2·16 = 32.