Question

Tyiesha says that if the magnitude of a vector u is zero, then u has to be a zero vector. Is she correct? Explain how

Answer 1

Answer:

Yes ,Tyiesha is correct.

Step-by-step explanation:

Lets take u vector

u =  ai + b j +ck

So the magnitude of vector u given as

$R=\sqrt{a^2+b^2+c^2}$

If the magnitude of above vector is zero then the values  a= 0 , b= 0 and c=0 should be zero.

a= 0 , b = 0 ,c = 0

So now by putting the values

u =  ai + b j +ck

u =  0 i + 0 j +0 k

u = 0  ,u is a zero vector.

It means that u should be zero vector.So Tyiesha is correct.