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2 years ago

Whats the simflied for 6x-2(3x-4)

Mathematics

1 answer:

Ne4ueva [31]2 years ago

3 0

Answer:

No solution

Step-by-step explanation:

6x - 2(3x - 4)

Distribute;

6x - 6x + 8

0 ≠ 8

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The ratio of girls to boys is 4:5 if there are 27 total students how many are girls? Boys?

kompoz [17]

4/9 x 27 = girls
12 girls

5/9 x 27 = boys
15boys

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2 years ago

The side of a square is Two raised to the seven halves power inches. Using the area formula A = s2, determine the area of the sq

AlladinOne [14]

Answer:

Step-by-step explanation:

Area of a square = s²

s is the side length of the square

Given

s = 2^{7 1/2}

s = 2^15/2

Area = ( 2^15/2)²

Area = 2^15

Hence two area of the square is 2^15 inches

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2 years ago

Read 2 more answers

The expression 10a+6c gives the cost (in dollars) for a adults and c children to eat at a buffet restaurant. A. The cost for 1 a

Liono4ka [1.6K]

Answer: The total cost is $\$62$ assuming the cost for 1 adult is $\$5$ and the cost for 1 child is $\$2$

Step-by-step explanation:

Assuming the cost for 1 adult is $\$5$ and the cost for 1 child is $\$2$ :

$a=\$5$ and $c=\$2$

Then the expression that gives the total cost $10 a+6c$ is solved as:

$10(\$5)+6(\$2)=\$62$

4 0

3 years ago

Can You Solve This?<br> 6 = 2(1+2) =

nata0808 [166]

Answer: 6 = 2(1+2), this is true.

Step-by-step explanation:

To solve this, 6 = 2(1 +2) =

This question is to proove that 2(1 +2) = 6

First we open the bracket:

(2 × 1) + (2 × 2)

Multiply 2 by 1 = 2

Multiply 2 by 2 = 4

2 + 4 = 6

I hope this helps.

8 0

2 years ago

Read 2 more answers

a circle has a center (3,5) and a diameter AB. The coordinates of A are (-4,6). what are the coordinates of B?

Kruka [31]

Find the length of the radius.

$r= \sqrt{(3-(-4))^2+(5-6)^2}
\\r = \sqrt{7^2+(-1)^2}
\\r= \sqrt{50} 
\\ r=5 \sqrt{2}$

Find the length of the diameter.

d = 2r = 2 × 5√2 = 10√2

Point B must lie on a line AC, where C is a center of a circle.
Find equation of line AC.
A(–4, 6), C(3, 5)

$y-y_1= \frac{y_2-y_1}{x_2-x_1}(x-x_1)
\\y-6= \frac{5-6}{3-(-4)} (x-(-4))
\\y-6=- \frac{1}{7} (x+4)
\\7y-42=-x-4
\\x+7y-38=0$

The distance from B(x, y) to C(3, 5) is 5√2.
$\sqrt{(x-3)^2+(y-5)^2}=5 \sqrt{2} 
 \\(x-3)^2+(y-5)^2=(5 \sqrt{2})^2 
\\(x-3)^2+(y-5)^2=50$

Solve system of equations.
$x+7y-38=0
\\(x-3)^2+(y-5)^2=50
\\
\\x=38-7y
\\(38-7y-3)^2+(y-5)^2=50
\\(35-7y)^2+(y-5)^2=50
\\1225-490y+49y^2+y^2-10y+25-50=0
\\50y^2-500y+1200=0
\\y^2-10y+24=0
\\y^2-6y-4y+24=0
\\y(y-6)-4(y-6)=0 \\(y-6)(y-4)=0 \\y_1=6,y_2=4
$

$x_1=38-7y_1=38-7 \times 6 = 38-42=-4
\\x_2=38-7y_2=38-7 \times 4 = 38-28=10
$

Point B could have coordinates
$\\
\\(x_1,y_1)=(-4,6),(x_2,y_2)=(10,4)
$

But (–4, 6) are the coordinates of point A.
Therefore, point B has coordinates (10,4).

8 0

3 years ago

Whats the simflied for 6x-2(3x-4)​

Whats the simflied for 6x-2(3x-4)