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Nastasia [14]
3 years ago
12

What is the absolute value equation for this graph

Mathematics
1 answer:
Svetlanka [38]3 years ago
4 0

Answer:

y = -|x - 2| + 4

Step-by-step explanation:

The parent function of the absolute value function is y = |x|. There is a negative reflection in the x-axis, a horizontal translation of 2 units right, and a vertical translation of 4 units up.

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PLEASE HELP with math
MArishka [77]

Answer:

1. 4 * 7 * 11 = 308

2. 7 * 7 * 4/2 = 98

3. 98 + 308 = 406

Hope this helps!

6 0
3 years ago
Solve by completing the square x^2-6x-4=0
Vesna [10]

Answer:

x = 3 ± \sqrt{13}

Step-by-step explanation:

x² - 6x - 4 = 0 ( add 4 to both sides )

x² - 6x = 4

To complete the square

add ( half the coefficient of the x- term)² to both sides

x² + 2(- 3)x + 9 = 4 + 9

(x - 3)² = 13 ( take square root of both sides )

x - 3 = ± \sqrt{13} ( add 3 to both sides )

x = 3 ± \sqrt{13}

6 0
2 years ago
8. A banker's loan officer rates applications for credit. The rates are normally distributed with a mean of 200 and a standard d
masha68 [24]

Answer:

802

Step-by-step explanation:

3 0
3 years ago
Abby has a beginning balance of $720 in her checking account. She writes two checks for $240 and $350 respectively and deposits
Yuliya22 [10]
<span>You made $18.10000000</span>
8 0
3 years ago
Use​ Newton's method to find an approximate solution of ln(x)=10-x. Start with x_0 =9 and find x_2 .
vova2212 [387]

Answer:

x₂ = 7.9156

Step-by-step explanation:

Given the function  ln(x)=10-x with initial value x₀ = 9, we are to find the second approximation value x₂ using the Newton's method. According to Newtons method xₙ₊₁ = xₙ -  f(xₙ)/f'(xₙ)

If f(x) = ln(x)+x-10

f'(x) = 1/x + 1

f(9) = ln9+9-10

f(9) = ln9- 1

f(9) = 2.1972 - 1

f(9) = 1.1972

f'(9) = 1/9 + 1

f'(9) = 10/9

f'(9) = 1.1111

x₁ = x₀ -  f(x₀)/f'(x₀)

x₁ = 9 -  1.1972/1.1111

x₁  = 9 - 1.0775

x₁  = 7.9225

x₂ = x₁ -  f(x₁)/f'(x₁)

x₂ = 7.9225 -  f(7.9225)/f'(7.9225)

f(7.9225) = ln7.9225 + 7.9225 -10

f(7.9225) = 2.0697 + 7.9225 -10

f(7.9225) = 0.0078

f'(7.9225) = 1/7.9225 + 1

f'(7.9225) = 0.1262+1

f'(7.9225) = 1.1262

x₂ = 7.9225 - 0.0078/1.1262

x₂ = 7.9225 - 0.006926

x₂ = 7.9156

<em>Hence the approximate value of x₂ is 7.9156</em>

7 0
3 years ago
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