Answer: 0.55567
Step-by-step explanation:
Given : A certain brand of refrigerator has a useful life that is normally distributed with mean 10 years and standard deviation 3 years. The useful lives of these refrigerators are independent.
i.e.

Let
and
are two randomly selected refrigerator's life whose sum will exceed third selected refrigerator
.
So that, 
Mean 
Standard deviation =


Z-score : ![z=\dfrac{X-E[x]}{\sqrt{Var[x]}}=\dfrac{0-1}{7.0156315694}\approx-0.14](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7BX-E%5Bx%5D%7D%7B%5Csqrt%7BVar%5Bx%5D%7D%7D%3D%5Cdfrac%7B0-1%7D%7B7.0156315694%7D%5Capprox-0.14)
Now , The probability that the total useful life of two(i..e n=2) randomly selected refrigerators will exceed 1.9 times the useful life of a third randomly selected refrigerator would be :-

Hence, the required probability is 0.55567.
Answer:
-17 < c < 5
Step-by-step explanation:
I think that's the answer
I can't confirm anything
Answer:
x > 9.
Step-by-step explanation:
Here it is just simplifying the inequality.
6 - 2/3x < x - 9
Add 2/3x to both sides.
6 < 5/3x - 9
Add 9 to both sides.
15 < 5/3x
Multiply by 3/5.
9 < x
Flip it.
x > 9.
Answer:
Volume = 6 * 6 * 6 = 216 m³
SA = 36 * 6 = 216 m²
Step-by-step explanation:
Answer:
Can u add the pic and I’ll answer it
Step-by-step explanation: