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Sav [38]
3 years ago
12

Solve for the equation 5= g/8 g=? g equals

Mathematics
1 answer:
shusha [124]3 years ago
4 0
STEP BY STEP BREAK DOWN.

rewrite the equation to g/8=5

multiply both sides by 8

cancel the common factors (cancel both 8s)

rewrite g=8 x 5

solve 8 x 5 (equals 40)

g=40
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Please help I'm struggling​
svetlana [45]

Answer:

the first is  1/5 what are the other options

Step-by-step explanation:

4 0
3 years ago
Solve -np-80&lt;60 for n. Show your work.<br><br> Solve 2a-5d=30 for d. Show your work.
xz_007 [3.2K]

-np-80 < 60\qquad\text{change the signs}\\\\np+80

------------------------------------------------------

2a-5d=30\qquad\text{subtract 2a from both sides}\\\\-5d=-2a+30\qquad\text{change the signs}\\\\5d=2a-30\qquad\text{divide both sides by 5}\\\\d=0.4a-6

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3 years ago
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Anna [14]
C is also the best answer
8 0
3 years ago
Read 2 more answers
If sine theta equals negative square root of three over two and pi less than theta less than three times pi over two, what are t
Romashka-Z-Leto [24]

Cosine theta equals the negative square root of three over two; tangent theta equals the negative square root of three over three is the correct answer.

<h3>What is angle measurement?</h3>

An angle measure is the measurement of the angle created by two rays or arms at a shared vertex in geometry. A protractor is used to measure angles in degrees (°).

Given data;

sin(1/2) = π/6

The value of the trignometric function are;

cos(π/6) = (√3)/2

tan(π/6) = 1/√3 = (√3)/3

In the second quadrant, where the cosine and tangent signs are both negative, is the angle of interest.

θ = 5π/6

cos(5π/6) = -(√3)/2

tan(5π/6) = -(√3)/3

Hence. cosine theta equals the negative square root of three over two; tangent theta equals the negative square root of three over three is the correct answer.

To learn more about the angle measurement, refer to the link;

brainly.com/question/14684647

#SPJ1

7 0
2 years ago
What is the domain of this graph​
Naddik [55]

Answer:

A

Step-by-step explanation:

b is the range

8 0
3 years ago
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