What is the density of a cube of wood with sides 5 cm and a mass of 109 g
2 answers:
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Answer:
608 ft²
Step-by-step explanation:
<u>1) Find the area of the bases</u>
where b is the base length and h is the height
Plug in b and h
Multiply the answer by 2 (because there are 2 bases)
A=96
Therefore, the area of the two bases is 96 ft².
<u>2) Find the area of the two sides facing up</u>
where l is the length and w is the width
Plug in l and w
Multiply the answer by 2 (because there are 2 sides)
A=320
Therefore, the area of these two sides is 320 ft².
<u>3) Find the area of the bottom side</u>
where l is the length and w is the width
Plug in l and w
Therefore, the area of this side is 192 ft².
<u>4) Add all the areas together</u>
96 ft² + 320 ft² + 192 ft²
= 608 ft²
Therefore, the surface area of the triangular prism is 608 ft².
I hope this helps!