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Ganezh [65]
3 years ago
10

A right triangle has one leg with a length of 48 and a hypotenuse with a length of 80 what is the length of the other leg

Mathematics
1 answer:
Reptile [31]3 years ago
7 0
A^2+b^2= c^2

48^2+b^2= 80^2

2304+b^2= 6400

Subtract 2304 from both sides.

b^2= 4096

Find the square root.

b= 64

I hope this helps!
~kaikers
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80 yd<br> 64 yd<br> b<br> What is the length of the missing leg?<br> =<br> yards
Mice21 [21]

Answer:

b = 48 yards

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Geometry</u>

  • Pythagorean Theorem: a² + b² = c²

Step-by-step explanation:

<u>Step 1: Define</u>

Leg <em>a</em> = <em>x</em>

Leg <em>b</em> = 64

Hypotenuse <em>c</em> = 80

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute:                    x² + 64² = 80²
  2. Isolate <em>x</em> term:              x² = 80² - 64²
  3. Exponents:                   x² = 6400 - 4096
  4. Subtract:                       x² = 2304
  5. Isolate <em>x</em>:                       x = √2304
  6. Evaluate:                       x = 48
8 0
3 years ago
2x+3=-7 what does x equal
ollegr [7]

Answer:-5

Step-by-step explanation:

2x+3=-7

2x=-7-3

x=-10/2

so,

x=-5

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svetlana [45]

Answer:

\huge\colorbox{violet}{✏﹏ \: ᴀɴsᴡᴇʀ \: }

{\boxed{\boxed{\tt { 1st / solution :-}}}} \

3x + 2y = 16 \\ 3(2) + 2(5) = 16 \\  6 + 10 = 16 \\ 16 = 16 \\  \\ x = 2 \: and \: y = 5

{\boxed{\boxed{\tt { 2nd / solution :-}}}} \

3x + 2y = 16 \\ 3(4) + 2(2) = 16 \\ 12 + 4 = 16 \\ 16 = 16 \\  \\ x = 4 \: and \: y = 2

{\boxed{\boxed{\tt { 3rd / solution :-}}}} \

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