The probability of a pea plant with genotype rryy producing a gamete with genotype ry is 1.
<h3>What would be the probability of a pea plant producing genotype ry from the genotype rryy?</h3>
- Probability is a measurement used in genetics to forecast the likelihood that a desired trait will be acquired by a child. The most easiest way to calculate the probabilities is to make a punnet square.
- The genotypes of a specific cross or breeding experiment are predicted using the Punnett square, a square diagram. It bears Reginald C. Punnett's name, who developed the method in 1905. Biologists use the figure to calculate the likelihood that a child will have a specific genotype.
- If we employ a punnet square for the genotype rryy producing a gamete with genotype ry the probability would be 1. You can refer the diagram for the understanding of the punnet square.
- F1 genotype: rryy
- F2 genotype: ry ry ry ry
- Thus the probability would be 1.
To learn more about genotype refer:
brainly.com/question/22117
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<em>I am going to assume you mean Buffalo, New York</em>
Buffalo, New York is commonly recognized as a 'safe haven' from the effects of climate change.
The reason why is that Buffalo New York is far away from seashore, since climate change also affects sea levels and such, Buffalo is an ideal place to escape the waters.
So in summary the population could significantly increase due to this fact.
Thank me later :)
(or just give brainliest)
Not necessarily, the equilibrium does not necessarily mean that the partial pressures are equal-- to explain this, you could look up the equilibrium constant of partial pressures. They are ratios, and not just equal partial pressures!
I believe it would die. A cell membrane is semi-permeable so it can get materials from outside the cell. If it couldnt do that, it would prevent it from functioning
Explanation:
you can see that one out of four offspring (25 percent) has the genotype PP, one out of four (25 percent) has the genotype pp, and two out of four (50 percent) have the genotype Pp. These percentages of genotypes are what you would expect in any cross between two heterozygous parents.
