Find the slope of the line that passes through (-19, -33) and (47, 5)

1 answer:

8 0

Hello there! Slope is rise/run. The formula for finding slope is y2 - y1 / x2 - x1, where you subtract the first x and y-coordinates from the second x and y-coordinates. In other words, the order that the coordinates show up for this problem will be used in that order. For this case, here are the numbers that will be used for each.

y2: 5
y1 : -33
x2: 47
x1: -19

Let's plug it in to get 5 - (-33) / 47 - (-19). Now, let's subtract. Just by looking at the numbers, we will actually be adding the numbers, because when you add a negative number, you actually add. So 5 + 33 is 38. 47 + 19 is 66. 38/66 is 19/33 in simplest form. There. The slope of the line is 19/33.

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-Dominant- [34]

Answer: 0.0031

Step-by-step explanation:

Binomial distribution formula :-

$P(x)=^nC_xp^x(1-p)^{n-x}$ , where P(x) is the probability of x successes in the n independent trials of the experiment and p is the probability of success.

Given : A binomial probability experiment is conducted with the given parameters.

$n=9,\ p=0.8,\ x\leq3$

Now, $P(x\leq3)=P(3)+P(2)+P(1)+P(0)$

$=^9C_3(0.8)^3(1-0.8)^{9-3}+^9C_2(0.8)^2(1-0.8)^{9-2}+^9C_1(0.8)^1(1-0.8)^{9-1}+^9C_0(0.8)^0(1-0.8)^9\\\\=\dfrac{9!}{3!6!}(0.8)^3(0.2)^6+\dfrac{9!}{2!7!}(0.8)^2(0.2)^7+\dfrac{9!}{1!8!}(0.8)(0.2)^8+\dfrac{9!}{0!9!}(0.2)^9=0.003066368\approx0.0031$