Answer:
The space inside the box = 2197 in³ - 1436.76 in³ is 760.245 in³.
Step-by-step explanation:
Here we have the volume of the cube box given by the following relation;
Volume of cube = Length. L × Breadth, B × Height, h
However, in a cube Length. L = Breadth, B = Height, h
Therefore, volume of cube = L×L×L = 13³ = 2197 in³
Volume of the basketball is given by the volume of a sphere as follows;
Volume = 
Where:
r = Radius = Diameter/2 = 14/2 = 7in
∴ Volume of the basketball = 
Therefore, the space inside the box that is not taken up by the basketball is found by subtracting the volume of the basketball from the volume of the cube box, thus;
The space inside the box = 2197 in³ - 1436.76 in³ = 760.245 in³.
Answer: n=37
Step-by-step explanation:
0.05n+0.10x2n=9.25
0.25n=9.25
n=9.25/0.25
n=37
<span> Sketch this, assuming the Earth is a sphere with radius R, so a plane slice through the periscope, ship and center of the Earth is a circle of radius R. Draw the lines out from the center (O) of the circle to point A at the top of the periscope and point B at the top of the ship. so that line AB is tangent to the circle at point C. That makes triangles OAC and OBC right triangles, each having the right angle at C. </span>
<span>From the problem, the lengths OA = R+5, OC = R, and OB=R+50. Label the lengths AC = p and BC= q, then use Pythagoras: </span>
<span>R² + p² = (R + 5)² </span>
<span>R² + q² = (R + 50)² </span>
<span>Solve those: </span>
<span>p² = (R + 5)² - R² = 10R - 25 </span>
<span>p = √(10R + 25) </span>
<span>q² = (R + 50)² - R² = 100R + 2500 </span>
<span>q = √(100R + 2500) </span>
<span>Find a good value for the radius R (in ft. units!) and calculate. The distance from periscope top to ship top is (p + q) feet. Convert that to miles for your answer.</span>
Answer:
the correct answer is 24.9
Step-by-step explanation:
Answer:
33.6
Step-by-step explanation:
.06 x 560
