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3 years ago

15

Rachel has 20 marbles in a jar. This table shows the number of blue, black, red, orange, and green marbles. What is the probabil

ity that if she randomly drew a marble out of the jar it would be orange?
A)15
B)14
C)25
D) 13

2 answers:

Tema [17]3 years ago

5 0

Assuming the numbers are percents, the answer is 25%, because 5/20 is 1/4, then convert the fraction to a percentage and you get 25%.

Elena-2011 [213]3 years ago

5 0

1/5 IS THE ANSWER/you plug the correct values into the formula Probability = number of desired outcomes/number of possible outcomes, you get Probability = 4/20. Simplify this fraction to 1%DIV%5. AND YOUR ANSWER WILL = 1/5

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Answer:

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$\tan(x+y)$ goes with $\sqrt{3}-2$

Step-by-step explanation:

$\cos(x+y)$

$\cos(x)\cos(y)-\sin(x)\sin(y)$ by the addition identity for cosine.

We are given:

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$\frac{\sqrt{2}}{2}\frac{-1}{2}-\frac{\sqrt{2}}{2}\frac{\sqrt{3}}{2}$

$\frac{-\sqrt{2}}{4}-\frac{\sqrt{6}}{4}$

$\frac{-\sqrt{2}-\sqrt{6}}{4}$

$-\frac{\sqrt{6}+\sqrt{2}}{4}$

Apply both of the givens to:

$\sin(x+y)$

$\sin(x)\cos(y)+\sin(y)\cos(x)$ by addition identity for sine.

$\frac{\sqrt{2}}{2}\frac{-1}{2}+\frac{\sqrt{3}}{2}\frac{\sqrt{2}}{2}$

$\frac{-\sqrt{2}+\sqrt{6}}{4}$

$\frac{\sqrt{6}-\sqrt{2}}{4}$

Now I'm going to apply what 2 things we got previously to:

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Multiply top and bottom by bottom's conjugate.

When you multiply conjugates you just have to multiply first and last.

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$-\frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}+\sqrt{2}} \cdot \frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}-\sqrt{2}}$

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Answer:

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