Is line AB tangent to the circle?
1 answer:
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Answer:
Step-by-step explanation:
To find the equation of a line using slope and a point, first use the slope to create the basic line using the slope and work from there.
For instance, the base equation here is
This line passes through the point (0, 0).
You can then plug in a value for x. In this case, use the value of 3, as it corresponds with your question.
A point on the line of y = 2x would thus be (3, 6).
To make the y-value equal -3, you must then subtract from the original equation. There are 9 units between 6 and -3, so you must subtract nine units in the equation. You should get this at the end:
Answers:
Domain = [-3, 3]
Range = [-1, 2]
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Explanation:
The domain is the set of all allowed x inputs. Visually, the left-most point is when x = -3, so -3 is the smallest allowed x input. We have a closed circle at this endpoint, so this endpoint x value is included. In contrast, if you had an open circle, then you would exclude the endpoint.
Similarly, we have a closed endpoint at the other side as well when x = 3. This is the largest allowed x value. The domain is the set of x values such that meaning x is between -3 and 3, including both endpoints. This translates to the interval notation of [-3, 3]. The square brackets say "include the endpoint".
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The range is the set of possible y outputs of a function. The lowest the function goes is when y = -1, and the highest is when y = 2. We include both endpoints. The range as a compound inequality is which converts to the interval notation of [-1, 2]