Question

Find K such that the points (-2, 5), (2, 8) and (6, K) are collinear.

Answer 1

Answer:

k = 11

Step-by-step explanation:

let the points be A(-2,5), B(2,8), C(6,K).

for the points to be collinear slope of line AB maust be equal to line BC.

slope of line AB = $\frac{8-5}{2+2}=\frac{3}{4}$

slope of line BC = $\frac{k-8}{6-2}=\frac{k-8}{4}$

therefore $\frac{k-8}{4}= \frac{3}{4}$

therefore k = 8 + 3

k = 11