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3 years ago

What is -5d+(-6)u-3?

Mathematics

1 answer:

hoa [83]3 years ago

3 0

Answer:-5d-6u-3

Step-by-step explanation:

-5d+(-6)u-3

-5d-6u-3

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A bag contains cars numbered from 1 to 14. Find the Probability of:

pochemuha

Prime numbers and numbers with a multiple of four that are between 1 and 14 include: 1, 2, 3, 4, 5, 7, 8, 12, 13.

There are 9 numbers listed.

9/14 = ~0.64285... or roghly 65.3%

B) Numbers between 1 and 14 with the multiples of 2 or 3 include: 2, 4, 6, 8, 9, 10, 12, 14.

There are 8 numbers listed.

8/14 = ~0.5714... or, about 57.14%

C) 3 and 4 is a list of two numbers.

2/14 = 1/7 = ~0.1429, or about 14.9%

D) There is a total of numbers equal to or less than 8 in a list of 1 and 14.

8/14 = ~0.5714... or, about 57.14%

3 0

2 years ago

Help please. I don't understand

inna [77]

In the middle of the first squre

7 0

2 years ago

A sociologist records the annual household income (in thousands of dollars) among a sample of families living in a high-crime ne

Gnoma [55]

Answer:

The lower quartile is $Q_1=33$ thousand dollars.

The median quartile is $Q_2=39$ thousand dollars.

The upper quartile is $Q_3=45$ thousand dollars.

Step-by-step explanation:

The lower quartile is the median value of the lower half of a data set at the 25th percentile of a distribution.

The median quartile is the median value of a data set at the 50th percentile of a distribution.

The upper quartile is the median value of the upper half of a data set at the 75th percentile of a distribution.

To locate each quartile in a data set, we follow four steps:

Step 1: Put the numbers in order: 23, 25, 33, 34, 39, 39, 44, 45, 48, 55

Step 2: The median is given by $\frac{n+1}{2}$ where n is all scores in the data set.

Because n = 10, the median position is $\frac{10+1}{2}=5.5$

The median is the average of the fifth and sixth positioned scores

$Q_2=\frac{39+39}{2} =39$

Step 3: Compute $\frac{n+1}{2}$ where n is all scores below $Q_2$ .

For scores below $Q_2$ , use only 23, 25, 33, 34, 39.

Because n = 5, the median position is $\frac{5+1}{2}=3$

The median is the third positioned score: $Q_1=33$

Step 4: Compute $\frac{n+1}{2}$ where n is all scores above $Q_2$ .

For scores above $Q_2$ , use only 39, 44, 45, 48, 55

Because n = 5, the median position is $\frac{5+1}{2}=3$

The median is the third positioned score: $Q_3=45$

7 0

3 years ago

If g(x) = -8x+1. Find g(-2).

puteri [66]

-8*-2+1=16+1=17
g(-2)=17

7 0

3 years ago

Read 2 more answers

2 1/2 x 3 1/5 fast please

vova2212 [387]

Step-by-step explanation:

Let's turn each mixed fraction into an improper fraction:

$2 \frac{1}{2} =\frac{2}{2} +\frac{2}{2} +\frac{1}{2} =\frac{5}{2}$

$3\frac{1}{5} =\frac{5}{5} +\frac{5}{5} +\frac{5}{5} +\frac{1}{5} =\frac{16}{5}$

Multiply:

$\frac{5}{2} \times \frac{16}{5} =\frac{80}{10}$

Simplify:

$\frac{80 \div 10}{10 \div 10} =\frac{8}{1} =8$

8 is your simplified product.

4 0

2 years ago