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3 years ago

10

Plz help me which number do i use for the hight

1 answer:

mr_godi [17]3 years ago

8 0

I believe you use the 12 inches one

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Need your help ASAP please help

eduard

His average is 86 so it is below 90. to get his average i just added all of his grades up to get 517 and then I divided 517 by 6 because thats how many grades he has and I got 86.

On the Grade row in the table it would go 83, 94, 79, 90, 96, 75 in order

The Above/Below 90 row would go -7, 4, 11, 7, -6, -3 in order

Lamont needs to get a 99 on his next test to have an average of exactly 90.

I HOPE THIS HELPED! PLEASE RATE ME AND MAKE MY ANSWER MOST BRAINLIEST!!

5 0

3 years ago

Given -16 = m over 5 -18; prove m=10

Aleks04 [339]

$- 16 = \frac{m}{5} - 18 \\ = > - 16 = \frac{m - 18 \times 5}{5} \\ = > -16 \times 5 = m - 90 \\ = > - 80 = m - 90 \\ = > - 80 + 90 = m \\ = > 10 = m \\ = > m = 10$
Hence provided

3 0

3 years ago

(2) Using the distance formula, d = √(x2 - x1)2 + (y2 - y1)2, what is the distance between point (-2, 2) and point (4, 4) rounde

monitta

Using the distance formula, $d = \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2 } \\$ , what is the distance between point (-2, 2) and point (4, 4) rounded to the nearest tenth?

Using the points given, plug them into the equation.

$d = \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2 } \\d = \sqrt{((4) - (-2))^2 + ((4) - (2)^2 } \\d=\sqrt{(4+2)^2 + (4-2)^2}\\d=\sqrt{(6)^2 + (2)^2} \\d=\sqrt{36+4} \\d=\sqrt{40} \\$

Plug this into a calculator and you get 6.32455532

Since you only need it up to the tenth (0.1), round up 6.32

<em>Five or more, let it soar. Four or less, let it rest.</em>

Since two is lower than four, we drop it.

Therefore, the distance between points (-2, 2) and (4, 4) is 6.3

Hope this helps ^w^

8 0

2 years ago

Drag each tile to the correct box. Not all tiles will be used.

Dmitry_Shevchenko [17]

Answer:

i think the answer is 10-11 but i'm not sure i'm sorry

Step-by-step explanation:

3 0

2 years ago

The number of girl child per family was recorded for 1000 families with 3 children. The data obtained was as follows: [2] Number

ira [324]

Answer:

$a.\ Probability = 0.426$

$b.\ Probability = 0.574$

Step-by-step explanation:

Given

$Total\ Families = 1000$

Number of Girls : 0 ----> 1 -----> 2 ------->3

Number of Families: 112 -> 314 --> 382 ---> 192

Solving (a): At most one girl

From the table, the number of families with at most one girl is: 112 + 314

i.e.

Number of Girls : 0 ----> 1

Number of Families: 112 -> 314

So, we have:

$At\ Most\ One\ Girl = 112 + 314$

$At\ Most\ One\ Girl = 426$

The probability is then calculated as:

$Probability = \frac{At\ Most\ One\ Girl}{Total}$

$Probability = \frac{426}{1000}$

$Probability = 0.426$

Solving (b): More girls

From the table, the number of families with more girl is: 382 + 192

i.e.

Number of Girls : -----> 2 ------->3

Number of Families: --> 382 ---> 192

So, we have:

$More\ Girls = 382 + 192$

$More\ Girls = 574$

The probability is then calculated as:

$Probability = \frac{More\ Girls}{Total}$

$Probability = \frac{574}{1000}$

$Probability = 0.574$

4 0

2 years ago