Question

If the probability of success during a single event of a geometric experiment is 0.03, what is the probability of success by the 13th event? Round your answer to the nearest tenth of a percent.

Answer 1

Answer:

The probability of success by the 13th event is:

                                   2.1%

Step-by-step explanation:

We know by geometric distribution the probability of a sucess at the kth experiment is given by:

             $P(X=k)=(1-p)^{k-1}\times p$

where p is the probability of the success.

Here we have:  p=0.03

and 1-p=0.97

and k=13

( since we are asked to find the probability by 13th event)

Hence, the probability is:

         $P(X=13)=(0.97)^{12}\times 0.03\\\\\\P(X=13)=0.02081$

In percent it is given by:

$P(X=13)=2.08\%$

To the nearest tenth it is: 2.1%

Answer 2

The answer is roughly 0.39 but not exactly including other details which were not mentioned