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3 years ago

6

A drawer contains 4 red socks, 7 white socks, and 11 blue socks. Without looking, you draw out a sock and then draw out a second

sock without returning the first sock. Find P(red, then white).

1 answer:

Nana76 [90]3 years ago

8 0

Total socks = 4 + 7+ 11 = 22
Red = 4
White = 7

P(red, then white) = (4/22)(7/21) = 2/33

Answer: 2/33

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Expand (x-2) (x-1). Must be in polynomial form.

Ludmilka [50]

To expand two terms such as these, we can use the method called FOIL (stands for First, Outer, Inner, Last). Here is what I mean:

We have two terms: (x - 2)(x - 1)

We should first multiply the First two terms of each term in order to complete the F stage:

(x)*(x) = $x^{2}$

So then, we take the two outer terms and multiply them together to complete the O stage:

(x)*(-1) = -x

So far we have two things that we have calculated; at the end of the FOIL process we will have four.

To keep going with the FOIL, we now multiply the two inner terms to complete the I stage:

(-2)*(x) = -2x

Last but not least, we need to complete the L stage - so we multiply the two last terms of each term:

(-2)*(-1) = 2

Now that we have our four terms, let us add them together and combine like terms:

$x^{2} + (-x) + (-2x) + 2$

Since -x and -2x both have the x portion in common and they are added together, we can add them to create one single term:

-x + (-2x) = -3x

So now that we have our terms completed, we can combine into one polynomial equation:

$x^{2} + (-3x) + 2$ or $x^{2} -3x+2$

6 0

3 years ago

prove or disprove that if you have an 8-gallon jug of water and two empty jugs with capacities of 5 gallons and 3 gallons, respe

Serjik [45]

Answer:

We can measure 4 gallon by successively.

Step-by-step explanation:

We have been given that you have an 8-gallon jug of water and two empty jugs with capacities of 5 gallons and 3 gallons, respectively. We are asked to prove or disprove that you can measure 4 gallon by successively pouring some of or all of the water in a jug into another jug.

First of all, we will pour 5 gallons of water from 8 gallon jug. Then we will pour 5 gallons of water from 5 gallon jug to 3 gallon jug. That will result in 2 gallons of water in 5 gallon jug.

Now, we will pour 3 gallons of water from 3 gallon jug to 8 gallon jug and pour 2 gallons from 5 gallon jug into 3 gallon jug. That will give us 6 gallons in 8 gallon jug and 2 gallons in 3 gallon jug and empty 5 gallon jug.

In our last step, we will fill 5 gallons jug from 8 gallon jug. After filling 5 gallon jug, we will fill 3 gallons jug from 5 gallon jug. Since 3 gallon jug already contains 2 gallons water, so it can only take one more gallon.

After pouring one gallon from 5 gallon jug, we will get 4 gallons water in 5 gallon jug.

Therefore, we can measure 4 gallon by successively pouring some of the water in a jug into another jug.

4 0

3 years ago

Adrian's CD player can hold six disks at a time and shuffles all of the albums and their songs. If he has thirteen CD's, how man

EastWind [94]

To answer this problem, the utilization of the provided formula is of utmost importance.

The formula to be used would be for the combination with no repetition since it is what is asked and possibly happens when involving the products mentioned in the problem. The formula would be

n! where in
------------- n = number of things to choose from
(n - r)! r! r = number of things needed to form

the symbol ! is called a factorial function which replaces the sequence of multiplying a number in a descending order.

lets substitute and solve

13!
--------------
(13 - 6)! 6!

13!
-------------
(7!) 6!

6,227,020,800
-------------------
5,040 x 720

6,227,020,800
-------------------
3,628,800

1,716

The answer would be 1,716.

6 0

3 years ago

A consumer organization estimates that over a 1-year period 20% of cars will need to be repaired once, 5% will need repairs

gtnhenbr [62]

Answer:

a) 0.5476

b) 0.0676

c) 0.4524

Step-by-step explanation:

Given this information, we can conclude that 74% of the cars won't need any repairs over a 1-year period (100 - 20 - 5 - 1 = 74%). And 26% will need at least 1 repair over a 1-year period.

P(car doesn't need repair) = 0.74

P (car needs repair) = 0.26

If you own two cars, the probability that:

<u>a) Neither will need repair:</u>

We need that car 1 won't need repair AND car 2 won't need repair.

=P(Car 1 doesn't need repair) x P(Car 2 doesn't need repair)

= 0.74 x 0.74 = 0.5476

The probability that neither will need repair is 0.5476.

<u>b) Both will need repair:</u>

We need that car 1 needs repair AND car 2 needs repair.

P(Car 1 needs repair) x P(Car 2 needs repair)

= 0.26 x 0.26 = 0.0676

The probability that both will need repair is 0.0676

<u>c) At least one car will need repair</u>

Car 1 needs repair or Car 2 needs repair or both need repair.

To solve this one, it's easier to use the complement of P(neither needs repair)

1 - P(neither needs repair)

1 - (0.74)(0.74) = 1 - 0.5476 = 0.4524

The probability that at least one car will need repair is 0.4524

4 0

3 years ago

Simplify. Write your answer using whole numbers and variables.

Andre45 [30]

Answer:

q + 7

Step-by-step explanation:

(q² + 4q − 21) / (q − 3)

Factor the numerator:

(q + 7) (q − 3) / (q − 3)

Divide:

q + 7

5 0

3 years ago