We are given that
Max's grade on the first math exam was a 94
so, first exam grade =94
His grade on his seond math exam was an 89
so, second exam grade =89
change in grade=(first exam grade)-(second exam grade)
change in grade=94-89
change in grade=5
Percentage = ( change in grade)/( first exam grade) *100
so, percentage is

so,
the percent of change in Max's grade to the nearest whole percentage was 5%..........Answer
Solve for w:
p = (1.2 w)/h^2
(1.2 w)/h^2 = (6 w)/(5 h^2):
p = (6 w)/(5 h^2)
p = (6 w)/(5 h^2) is equivalent to (6 w)/(5 h^2) = p:
(6 w)/(5 h^2) = p
Multiply both sides by (5 h^2)/6:
Answer: w = (5 h^2 p)/6
Answer:
3,750 cars.
Step-by-step explanation:
We are given that the equation:

Models the relationsip between <em>y</em>, the number of unfilled seats in the stadium, and <em>x</em>, the number of cars in the parking lot.
We want to determine the number of cars in the parking lot when there are no unfilled seats in the stadium.
When there are no unfilled seats in the stadium, <em>y</em> = 0. Thus:

Solve for <em>x</em>. Subtract 9000 from both sides:

Divide both sides by -2.4:

So, there will be 3,750 cars in the parking lot when there are no unfilled seats in the stadium.
Answer: C. The functions will have the same input when y=0.
Step-by-step explanation: