Question

The function f(x)=x^2+4.2x+3.6 has an axis of symmetof x=-2-. What is the minimum value of the function

Answer 1

ANSWER

The minimum value is -0.8

EXPLANATION

The given

$f(x)=x^2+4.2x+3.6$

The minimum value is the y-value of the vertex (minimum point).

To find the minimum value of the function, we substitute x=-2 into the function to get;

$f( - 2)=( - 2)^2+4.2( - 2)+3.6$

$f( - 2)=4 - 8.4+3.6 = - 0.8$

The minimum value is -0.8