All categories

3 years ago

The function f(x)=x^2+4.2x+3.6 has an axis of symmetof x=-2-. What is the minimum value of the function

Mathematics

1 answer:

Pepsi [2]3 years ago

8 0

ANSWER

The minimum value is -0.8

EXPLANATION

The given

$f(x)=x^2+4.2x+3.6$

The minimum value is the y-value of the vertex (minimum point).

To find the minimum value of the function, we substitute x=-2 into the function to get;

$f( - 2)=( - 2)^2+4.2( - 2)+3.6$

$f( - 2)=4 - 8.4+3.6 = - 0.8$

The minimum value is -0.8

You might be interested in

If f(x) = 1-x^2+x^3, then f(-1)=

Yuri [45]

Answer: -1

Step-by-step explanation:

1-(-1^2)+(-1^3) = 1-1+(-1)= -1

7 0

2 years ago

I 8. Classify 8 as a perfect square, a perfect cube, both, or neither.

Murljashka [212]

Answer:

It's a perfect cube, but not a perfect square.

Step-by-step explanation:

2^3 = 8, meaning 8 is a perfect cube. But since 2^2 = 4 and 3^2 = 9, and 8 is in between, 8 is not a perfect square.

I hope this helped.

7 0

3 years ago

Order of Operation

Sphinxa [80]

45(x)-20

x=hours

7 hours

x=7

45(7)-20 =295

4 0

2 years ago

Read 2 more answers

Peter plans to build a tree house in his back yard. He needs to know how many square feet of lumber he should buy for the floor.

11Alexandr11 [23.1K]

Answer:

20n

Step-by-step explanation:

Multiply square feet per person times the number of persons to find square feet.

The units analysis looks like this:

$\dfrac{\text{ft}^2}{\text{person}}\times \text{persons}=\text{ft}^2\\\\20\dfrac{\text{ft}^2}{\text{person}}\times n\,\text{persons}=20n\,\text{ft}^2$

4 0

3 years ago

Read 2 more answers

A purchaser of electric relays buys from two suppliers, A and B. Supplier A supplies two of every three relays used by the compa

inessss [21]

Answer:

The probability that at most 38 of the 60 relays are from supplier A is P(X≤38)=0.3409.

Step-by-step explanation:

We can model this question with a binomial distribution random variable.

The sample size is n=60.

The probability that the relay come from supplier A is p=2/3 for any relay.

If we use a normal aproximation, we have the mean and standard deviation:

$\mu=np=60*(2/3)=40\\\\\sigma=\sqrt{npq}=\sqrt{60*(2/3)*(1/3)} =3.65$

The probability that at most 38 of the 60 relays are from supplier A is P(X≤38)=0.3409:

$P(X\leq38)=P(X$

5 0

3 years ago