Answer:
a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Step-by-step explanation:
I am going to solve this question treating these events as Venn probabilities.
I am going to say that:
Event A: Person has type A blood.
Event B: Person has Rh- factor.
43% of people have type O blood
This means that 
15% of people have Rh- factor
This means that 
52% of people have type O or Rh- factor.
This means that 
a. Find the probability that a person has both type O blood and the Rh- factor.
This is

With what we have

0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b. Find the probability that a person does NOT have both type O blood and the Rh- factor.
1 - 0.06 = 0.94
0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
You would do 300• 31/100 to get 90. I’m pretty sure that’s right
8000-4.989 so when you see the word less than it means that you have to subtract and more than you have to add so the answer for this question will be 7,995.011
Step 1: move all terms to one side
7 + 2x^2 - 10x = 0
Step 2: Use the quadratic formula
X = 10 + 2(square root of 11). 10-2 _/—-11
————————————. ——————
4. , 4
Step 3: Simplify solutions
X= 5 + (square root of 11) 5 - (square root 11)
——————————- , ————————
2. 2