Question

What is the area of this figure?

Answer 1

Hello!

The answer is: $189cm{2}$

Why?

There are three figures in the shown figure: two right rectangles and one square, we need to calculate each figure area and then, we need to sum in order to know the total figure area.

From the figure, we can extract the information that we need:

For the triangles, both are right triangles with the same dimensions:

$base=12cm\\height=9cm$

For the square:

$base=9cm\\height=9cm$

Area calculations:

Triangle area is equal to the product between its height and base dimensions divided into 2, So:

$TriangleArea=\frac{9cm*12cm}{2}=54cm^{2}$

Since we have two equal trianges, the second triangle area is also $54cm^{2}$

Square area is equal to the product between its height and base, so:

$SquareArea=9cm*9cm=81cm^{2}$

Therefore,

The total area will be:

$TotalArea=TrianglesArea+SquareArea=54cm{2} + 54cm{2} + 81 cm{2}=189cm{2}$

Have a nice day!

Answer 2

[ Answer ]

$\boxed{\bold{189 \ cm^{2} }}$

[ Explanation ]

• Find Area Of Figure

--------------------------------

1 Triangle

1 Triangle

1 Square

Area Of Triangle - $\frac{1}{2}Base$ · Height

Area Of Square - Base · Height

Triangle:

Height - 12

Base - 9

4.5 · 12 = 54

54 + 54 = 108

2 Triangles = 108

--------------------

Square:

Base - 9

Height - 9

9 * 9 = 81

--------------------

81 + 108 = 189

$\boxed{\bold{[] \ Eclipsed \ []}}$