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lara [203]
3 years ago
10

A support beam to be placed at a 28° angle of elevation so that the top meets a vertical beam 1.6 meters above the horizontal fl

oor. Thanks vertical beam meets the floor at a 90° angle.
Law of sin: sin(A)/a=sin(B)/b=sin(C)/c
Approximately how far the vertical beam should the lower end of the support be placed along the horizontal floor



A)3.0 meters
B)3.4 meters
C)3.9 meters
D)4.4 meters
Mathematics
1 answer:
daser333 [38]3 years ago
5 0
1.6/sin(28)
The answer is B
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The random sample of the students is an illustration of sampling

The chi-square test for goodness of fit is inappropriate because the variable under study is not categorical.

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The dataset is given as:

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The variable of the above dataset is a not a categorical dataset.

One of the conditions of the chi-square test for goodness of fit test is that the variable under study must be categorical.

Hence, the chi-square test for goodness of fit is inappropriate because the variable under study is not categorical.

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2 years ago
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Arthemeatic sequence
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6 0
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Solve |5 - 8x| - 7 &lt; 8<br><br>​
sammy [17]
Move all terms not containing
|
5
−
8
x
|
|
5
-
8
x
|
to the right side of the inequality.
Tap for fewer steps...
Add
7
7
to both sides of the inequality.
|
5
−
8
x
|
<
8
+
7
|
5
-
8
x
|
<
8
+
7
Add
8
8
and
7
7
.
|
5
−
8
x
|
<
15
|
5
-
8
x
|
<
15
Remove the absolute value term. This creates a
±
±
on the right side of the inequality because
|
x
|
=
±
x
|
x
|
=
±
x
.
5
−
8
x
<
±
15
5
-
8
x
<
±
15
Set up the positive portion of the
±
±
solution.
5
−
8
x
<
15
5
-
8
x
<
15
Solve the first inequality for
x
x
.
Tap for more steps...
x
>
−
5
4
x
>
-
5
4
Set up the negative portion of the
±
±
solution. When solving the negative portion of an inequality, flip the direction of the inequality sign.
5
−
8
x
>
−
15
5
-
8
x
>
-
15
Solve the second inequality for
x
x
.
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x
<
5
2
x
<
5
2
Set up the intersection.
x
>
−
5
4
x
>
-
5
4
and
x
<
5
2
x
<
5
2
Find the intersection between the sets.
−
5
4
<
x
<
5
2
-
5
4
<
x
<
5
2
The result can be shown in multiple forms.
Inequality Form:
−
5
4
<
x
<
5
2
-
5
4
<
x
<
5
2
Interval Notation:
(
−
5
4
,
5
2
)
(
-
5
4
,
5
2
)

6 0
3 years ago
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