Question

Given that ABCD is a rhombus, find the value of x. (X+14)

Answer 1

Answer:

option B. $x=38^o$

Step-by-step explanation:

we know that

1) The two diagonals of a rhombus are perpendicular

2) The sum of the interior angles in any triangle must be equal to 180 degrees

Let

O ----> the intersection point of the diagonals of the rhombus

In the right triangle OAD

$x^o+(x+14)^o+90^o=180^o$

solve for x

$x^o+(x+14)^o=90^o$

$2x=90^o-14^o$

$2x=76^o$

$x=38^o$