All categories

2 years ago

Write an equation in point-slope form of the line that passes through the given point and with the given slope m.

Mathematics

2 answers:

Hunter-Best [27]2 years ago

4 0

Step-by-step explanation:

Just use the equation y-y1=m(x-x1)

Where you plug in (-8,5) at your and x1. Then you do the Algebra.

mart [117]2 years ago

3 0

Using point slope formula it would be
Y - 5 = 2 • ( x + 8)

You might be interested in

Select the correct answer. Which expression represents the series ? 1+5+25+125+625? creating and solving formulas for geometric

Art [367]

Answer:

The given series can be written as

∑ (5)^i

i = 0

We know that the series is

1+5+25+125+625

This is equal to

(5)^0 + (5)^1 + (5)^2 + (5)^3 + (5)^4

Thus,

For i from 0 to 4,

We get the general representation.

3 0

3 years ago

Which of the following expressions entered into a graphing calculator will

Tanya [424]

Answer: B (0.17, 2.33)

Step-by-step explanation:

A P E X

5 0

2 years ago

How many kilometers are there in 4 miles?

raketka [301]

There are 6.4 Kilometers in 4 miles

3 0

2 years ago

Sara would like to open a bank account. What will she need to do this? Check all that apply.

svet-max [94.6K]

Where are the examples?

4 0

3 years ago

Read 2 more answers

Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s

Nataliya [291]

Answer:

$f(x)=\frac{1}{2}x^2-4x+5$

Step-by-step explanation:

A parabola is written in the form

$f(x)=a((x-h)^2+k)$ (1)

where:

$h$ is the x-coordinate of the vertex of the parabola

$ak$ is the y-coordinate of the vertex of the parabola

$a$ is a scale factor

For the parabola in the problem, we know that the vertex has coordinates (4,-3), so we have:

$h=4$ (2)

$ak=-3$

From this last equation, we get that $a=\frac{-3}{k}$ (3)

Substituting (2) and (3) into (1) we get the new expression:

$f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3$ (4)

We also know that the parabola contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

$-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6$

So we also get:

$a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}$

So the equation of the parabola is:

$f(x)=\frac{1}{2}((x-4)^2 -6)$ (5)

Now we want to rewrite it in the standard form, i.e. in the form

$f(x)=ax^2+bx+c$

To do that, we simply rewrite (5) expliciting the various terms, we find:

$f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5$

6 0

3 years ago