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myrzilka [38]
3 years ago
8

Jose is now six years older than John. In two years, Jose will be twice as old as John. How old is John now ?

Mathematics
1 answer:
sammy [17]3 years ago
7 0
John is currently 6 years old. 

You can find this by setting John's original age as x and Jose's original age as x + 6. Then we can set up an equation adding two to both. 

John's new age = x + 2
Jose's new age = x + 8

Now we can multiply John's new age by two and set equal to Jose's age, since Jose's new age is twice as much as John's. 

2(x + 2) = x + 8
2x + 4 = x + 8
x + 4 = 8
x = 4

This means John's original age is 4 and his new age is 6. 
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SOLVING EACH SYSTEM BY ELIMINATION <br><br><br> x+3y=5 x=-6y+14<br><br><br> HELP
nata0808 [166]

Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

Step-by-step explanation:

Given the system of the equations

x+3y=5;\:x=-6y+14

solving by elimination method

\begin{bmatrix}x+3y=5\\ x=-6y+14\end{bmatrix}

\mathrm{Arrange\:equation\:variables\:for\:elimination}

\begin{bmatrix}x+3y=5\\ x+6y=14\end{bmatrix}

x+6y=14

-

\underline{x+3y=5}

3y=9

\begin{bmatrix}x+3y=5\\ 3y=9\end{bmatrix}

solve 3y=9 for y:

3y=9

\frac{3y}{3}=\frac{9}{3}

y=3

\mathrm{For\:}x+3y=5\mathrm{\:plug\:in\:}y=3

Solve x+3\cdot \:3=5 for x:

x+3\cdot \:3=5

x+9=5

x=-4

Therefore,

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

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Step-by-step explanation:

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Hope this helped☺☺
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