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3 years ago

9

Dan earns £9.80 per hour. How much will he earn for 8 hours work?

2 answers:

jok3333 [9.3K]3 years ago

7 0

Answer:

78.40

Step-by-step explanation:

Take 9.80 and times it by 8 to get 78.40

vovikov84 [41]3 years ago

6 0

Answer:

£78.40

Step-by-step explanation:

£9.80 (Per hour payment) times 8 hours (The time span) equals £78.40

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each truck in the line weigh two tons more than the truck before it. the trucks weigh a total of 32 tons.how many pounds does a

mixer [17]

If there are 4 trucks then the first truck weighs x
then x+2tons
then x+4tons
then x+6tons = 32tons
so 4x+12=32
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x=5
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3 years ago

Solving equations (algebra). Thank you!

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Answer:

$\large\boxed{\dfrac{1}{x^2}+x^2=23}$

Step-by-step explanation:

$\left(\dfrac{1}{x}+x\right)^2=25\qquad\text{use}\ (a+b)^2=a^2+2ab+b^2\\\\\left(\dfrac{1}{x}\right)^2+2(x\!\!\!\!\diagup)\left(\dfrac{1}{x\!\!\!\!\diagup}\right)+x^2=25\\\\\dfrac{1}{x^2}+2+x^2=25\qquad\text{subtract 2 from both sides}\\\\\dfrac{1}{x^2}+x^2=23$

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3 years ago

Albert cuts lawns for neighbors in charges $25 per week. He cuts the lawns for all 15 of his customers every week for 24 weeks d

slava [35]

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3 years ago

A student needs to select 3 books from 3 different mathematics, 3 different physics and 1 history books. What is the probability

Gnesinka [82]

Answer:

Probability that one of them is mathematics and other two are either physics or history books = 0.51

Step-by-step explanation:

Given - A student needs to select 3 books from 3 different mathematics, 3 different physics and 1 history books.

To find - What is the probability one of them is mathematics and other two are either physics or history books ?

Solution -

Given that,

A student needs to select 3 books from 3 different mathematics, 3 different physics and 1 history books.

So,

Total number of books = 3 + 3 + 1 = 7

The student has to select 3 books

So, Total number of ways = $^{7} C_{3}$ = 35

So,

Probability that one of them is mathematics and other two are either physics or history books is -

= $\frac{^{3} C_{1}. ^{4} C_{2} }{^{7} C_{3}}$

= $\frac{(3)(6)}{35}$

= $\frac{18}{35}$

= 0.51

⇒Probability that one of them is mathematics and other two are either physics or history books = 0.51

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Step-by-step explanation:

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