<span>9v^2=25
v^2 = 25/9
v^2 = (5/3)^2
v = + 5/3 and v = -5/3
hope it helps</span>
The described picture frame can be visualized into two separate parts. The first area is equal to the area using the outermost dimensions for the length and width.
Area = Length x Height
Area = (20 in) x (14 in)
Area = 280 in²
We are given that the area is only equal to 192 in². We subtract this value from the computed area.
Difference = 280 in² - 192 in²
difference = 88 in²
This area is equal to the area of the hollow space inside the frame. That is equal to,
height = 20 in - 2x
length = 14 in - 2x
The area,
88 = (20 - 2x)(14 - 2x)
Simplify the right hand side of the equation.
88 = 280 - 68x + 4x²
Divide the equation by 4,
22 = 70 - 17x + x²
Transposing,
x² - 17x - 48 = 0
The factors of the equation is 58.2.
Thus, the thickenss is equal to 58.2 in
You need to solve this for h(t)=0
<span>-16t^2-30t+124=0
This has two solutions, one is negative that does not make sense as time cannot be negative.
The positive solution is t=2
So the interval where it is in the air is [0;2)
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