<span>Multiply the numerators together.Multiply the denominators together.Simplify the fraction.<span>Convert the improper fraction (if it is improper) to a mixed fraction answer. To do this divide the denominator into the numerator finding the quotient and remainder.</span></span>
Answer:
so to get a 85 you would have to make 20 to 45 free throws without any fouls and anyone taking the basketball away from you if you do then it is for sure a 0 and it will go on your record
Step-by-step explanation:
Inconsistent system of equation consists of equations whose graphs do not intersect (they are parallel lines) and there is no solution.
Dependent system of equations consists of equations that are same (their graph is the same) but written in different form.
Let us analyze the equations:
5x+<span>10y+15z=60 (1)
</span>2x+4y+6z=60 (2)
<span>x+2y+3z=60 (3)
We can divide the first one by 5 </span><span>to obtain the same left side as in equation (3), and to see if they are dependent:
x+2y+3z=12
</span>which is not the same as <span>x+2y+3z=60.
</span>They are not dependent (they are independent).<span>
We can divide the second one by 2 to obtain the same left side as in equation (3), and to see if they are dependent:
</span><span>x+2y+3z=30 (2) divided by 2
which is not the same as </span><span>x+2y+3z=60. They are not dependent (they are independent).
The graphs of the three functions are parallel so, they are inconsistent.
Solution: inconsistent and independent
</span>
Let's pick an odd number hmmm say 7, 7 is odd.
what's the first consecutive integer after it? well is 8, so is just one hop away from 7, or 7+1.
so for any odd integer, the next even is just one hop away.
Answer:
The 95% confidence interval for the mean birth weight of all non-premature babies is between 3350.4 grams and 3662.4 grams. This means that we are 95% sure that true mean birth weight of all non-premature babies is in this interval.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 41 - 1 = 40
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 40 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 2.0211
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 3506.4 - 156 = 3350.4 grams
The upper end of the interval is the sample mean added to M. So it is 3506.4 + 156 = 3662.4 grams
The 95% confidence interval for the mean birth weight of all non-premature babies is between 3350.4 grams and 3662.4 grams. This means that we are 95% sure that true mean birth weight of all non-premature babies is in this interval.
