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3 years ago

Write an equation of the line that passes through (2, 7) and (0, −5) y=

2 answers:

8 0

First, solve for slope.
Formula for slope: $\frac{y2-y1}{x2-x1}$
Plug in values: $\frac{-5-7}{0-2} = \frac{-12}{-2} = 6$
Slope: $6$
Second, we must plug into point-slope form.
Formula for point-slope: $y - y1 = m(x-x1)$
Plug in the values: $y - 7 = 6(x-2)$
Solve.
$y - 7 = 6(x-2) 

y - 7 = 6x - 12

Add 7 both sides. 

y = 6x - 5$
So the equation is: $y = 6x - 5$

viva [34]3 years ago

4 0

((-5) - 7) / (0-2) = slope because equation for slope is y2 - y1 / x2 - x1. Then the y-intercept is already given. So slope is -12/-2 = 6 so, y= mx + b, meaning mx is slope of -6x and b being -5. Therefore the equation is y = -6x - 5. Hope this helps!

You might be interested in

Solve the equation. -9x + 1 = -x + 17

ddd [48]

Answer:

The value of $x$ :

$x = -2$

Step-by-step explanation:

Find the value of $x$ :

$-9x + 1 = -x + 17$

-Add both sides by $x$ :

$-9x + 1 + x = -x + x + 17$

$-8x + 1 = 17$

-Subtract both sides by $1$ :

$-8x + 1 - 1 = 17 - 1$

$-8x = 16$

Divide both sides by $-8$ :

$\frac{-8x}{-8} = \frac{16}{-8}$

$x = -2$

So, the final answer would be $x = -2$ .

4 0

3 years ago

Read 2 more answers

If f(x)=2x-5, which expression represents f(x+1)? A) 2x-3, B) 2x-4, C)2x-5, D)2x+7

Dovator [93]

F(x)=x^2+2x+1 & g(x)=3(x+1)^2
now, f(x)+g(x)
=x^2+2x+1+3(x+1)^2
=x^2+2x+1+3(x^2+2x+1)
=x^2+2x+1+3x^2+6x+3
=4x^2+8x+4<===answer(c)
next:
f(x)=x^2-1 & g(x)=x+3
now, f(g(x))=(x+3)^ -1
=x^2+6x+9-1
=x^2+6x+8<====answer(b)
i solve two of ur problems.
now try the 3rd one that is similar to no. 1
and try the last two urself.

5 0

3 years ago

3. List the coefficients in the expression below. 14x - 7x + 1-2x

elena-14-01-66 [18.8K]

Answer:

14, -7, -2

Step-by-step explanation:

The coefficient is the number that multiplies the variable, so list the numbers that fall under that definition:

14x - 7x + 1 - 2x

↑ ↑ ↑

14 -7 -2

The coefficients in the expression are 14, -7, and -2.