Ask question

Ask question

All categories

2 years ago

8

ABCD∼EFGH AD=45 in. , EH=75 in. , and AB=30 in. What is EF ?

1 answer:

Marrrta [24]2 years ago

3 0

EF = 50 in.

In similar figures, corresponding sides are proportional. We use the similarity statement ABCD~EFGH to write a proportion:

$\frac{AB}{EF}=\frac{AD}{EH}
\\
\\ \frac{30}{x}=\frac{45}{75}$

Cross multiply the proportion:
45*x = 75*30
45x = 2250

Divide both sides by 45:
45x/45 = 2250/45
x = 50

You might be interested in

CATHERINE'S MOTHER IS WRAPPING A BOX THAT IS 12 INCHES LONG X 8 INCHES WIDE X 10 INCHES IN HIGH. HOW MANY SQUARE INCHES OF WRAPP

taurus [48]

12 x 8= 96
10 x 8 =80
12 × 10= 120
120+80+96= 296

8 0

3 years ago

Need help!!! I don't understand it..

JulsSmile [24]

Okay so every triangle will have 3 angles that add to 180 degrees. You are given that A=65 which means that B + C will have to add to 115. You are given that B= (3x-10) and C=2x, plug this into B+C=115. So
3x-10+2x=115, isolate x, 5x=125, divide both sides by 5 and you get that x=25. This makes B=65, and C=50. Just to check, if you add these together you get 180 degrees.

6 0

2 years ago

The area of triangle EFG js 34.8 square units. What is the

hichkok12 [17]

Answer:

A. 29 units

Step-by-step explanation:

3 0

3 years ago

irina1246 [14]

Answer:

1/6

Step-by-step explanation:

5/6 divided by 5 is 1/6

6 0

2 years ago

Read 2 more answers

Can someone plz help me with this!

asambeis [7]

Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

$2x+y=10\\x-3y=-2$

To solve, start by isolating your first equation for y.

$2x+y=10\\y=-2x+10$

Now, plug this value of y into your second equation.

$x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4$

System #2: x=1

$x+2y=5\\2x+y=4$

Isolate your second equation for y.

$2x+y=4\\y=-2x+4$

Plug this value of y into your first equation.

$x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1$

System #3: x=6

$5x+y=33\\x=18-4y$

Isolate your first equation for y.

$5x+y=33\\y=-5x+33$

Plug this value of y into your second equation.

$x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6$

System #4: all real numbers (not included in your diagram)

$y=13-2x\\8x+4y=52$

Plug your value of y into your second equation.

$8x+4(13-2x)=52\\8x+52-8x=52\\0=0$

<em>all real numbers are solutions</em>

System #5: x=2

$x+3y=5\\6x-y=11$

Isolate your second equation for y.

$6x-y=11\\-y=-6x+11\\y=6x-11$

Plug in your value of y to your first equation.

$x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2$

System #6: no solution (not included in your diagram)

$2x+y=10\\-6x-3y=-2$

Isolate your first equation for y.

$2x+y=10\\y=-2x+10$

Plug your value of y into your second equation.

$-6x-3(-2x+10)=-2\\-6x+6x-30=-2\\-30=-2$

<em>no solution</em>

System #7: x=3

$y=10+x\\2x+3y=45$

Plug your value of y into your second equation.

$2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3$

3 0

2 years ago