3 years ago

6

Mathematics

1 answer:

mihalych1998 [28]3 years ago

7 0

Answer:

4 hours

Step-by-step explanation:

You might be interested in

5c squared- d squared+3/2c - 4d...c= -1. d= -4

riadik2000 [5.3K]

For this case we have the following expression:

$5c ^ 2-d ^ 2 + \frac {3} {2} c-4d$

We must find the value of the expression when:

$c = -1\\d = -4$

Substituting we have:

$5 (-1) ^ 2 - (- 4) ^ 2 + \frac {3} {2} (- 1) -4 (-4) =\\5 (1) -16- \frac {3} {2} + 16 =\\5-16- \frac {3} {2} + 16 =\\-11- \frac {3} {2} + 16 =\\- \frac {25} {2} + 16 =\\\frac {-25 + 32} {2} =\\\frac {7} {2}$

Finally, the value of the expression is:

$\frac {7} {2}$

ANswer:

$\frac {7} {2}$

5 0

3 years ago

Simplify<br><img src="https://tex.z-dn.net/?f=%20%7Ba%7D%5E%7B%20-%202%7D%20%20%7Bb%7D%5E%7B3%7D%20" id="TexFormula1" title=" {a

DaniilM [7]

Answer:

Below

Step-by-step explanation:

● a^(-2) *b^3

●(1/a^2) *b^3

● b^3 / a^2

5 0

3 years ago

SOLVE BY ELIMINATION.<br><br> x-2y=2<br> 3x+y=6

USPshnik [31]

$\left \{ {{x-2y=2} \atop {3x+y=6\ |\cdot2}} \right. \\\\ \left \{ {{x-2y=2} \atop {6x+2y=12}} \right. \\+-----\\\\7x=14\ \ \ \ |:7\\x=2\\\\2-2y=2\\-2y=2-2\\-2y=0\\y=0\\\\ \left \{ {{y=0} \atop {x=2}} \right.$