Question

The measure of one of the small angles of a right triangle is 18 less than twice the measure of the other small angle. Find the measure of both angles. Use integers only

Answer 1

Answer:

36° and 54°

Step-by-step explanation:

We are given that one of the small angles of a right angled triangle is 18 less than twice the measure of the other small angle.

We are to find the measure of both angles.

Assuming $x$ to be the other small angle, 8 less than twice the measure of the other small angle = $2x-18$.

Summing all three angles up ti get:

$x+(2x-18)+90=180$

$3x=180-90+18$

$3x=108$

$x=\frac{108}{3}$

x = 36°

So other angle will be $2(36)-18=$ 54°.

Answer 2

Answer:

36° and 54°

Step-by-step explanation:

let x be one of the smaller angles, then the other smaller angle is 2x - 18 ( 18 less than twice the other )

Since it is a right triangle then the sum of the 2 smaller angles equals 90, so

x + 2x - 18 = 90

3x - 18 = 90 ( add 18 to both sides )

3x = 108 ( divide both sides by 3 )

x = 36

One angle = 36°

the other angle = (2 × 36) - 18 = 72 = 18 = 54°