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Lemur [1.5K]
3 years ago
15

Read the given chemical reaction. C2H6 + O2 → CO2 + H2O How many moles of O2 are required to react completely with 3.2 moles of

C2H6? 3.5 moles of O2 6.5 moles of O2 10.4 moles of O2 11.2 moles of O2
Chemistry
1 answer:
Vesnalui [34]3 years ago
3 0
<h2>Hello!</h2>

The answer is: 11,2 moles of O2

<h2>Why?</h2>

First, we need to balance the equation in order to calculate how many moles reacts,

The balanced equation is:

2 C2H6 + 7 O2 = 4 CO2 + 6 H2O

So, from the equation we have that 2 moles of C2H6 reacts with 7 moles of O2, knowing that we can calculate how many moles of O2 are required to react completely with 3.2 moles of C2H6:

3,2moles(C2H6)*\frac{7 moles (O2)}{2moles(C2H6)} =11,2 moles(O2)

So, we need 11,2 moles of O2 to react completely with 3,2 moles of C2H6.

Have a nice day!

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Answer:

3 mm is equal to 1.547244 inches. To do the calculation, use our online calculator. In the box next to “millimeters”, type 39.3. Once you have entered the number, the calculator displays the results. Once you have taken note of the numbers, click the reset button if you want to make other conversions.

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4 years ago
Write the IUPAC name OF THE FOLLOWING COMPOUNDS
goldenfox [79]

Answer:

Explanation:

a) 2 chloro butane

b) 2-3 dimethyl butane

c) 2 bromo 3 nitro pentane

d) 2-3 trimethyl pentane

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7 0
4 years ago
Which gas will effuse at the rate closest At a particular pressure and temperature, nitrogen gas effuses at the rate of 79mLs. U
Contact [7]

Answer : The rate of effusion of sulfur dioxide gas is 52 mL/s.

Solution :

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

R\propto \sqrt{\frac{1}{M}}

or,

(\frac{R_1}{R_2})=\sqrt{\frac{M_2}{M_1}}       ..........(1)

where,

R_1 = rate of effusion of nitrogen gas = 79mL/s

R_2 = rate of effusion of sulfur dioxide gas = ?

M_1 = molar mass of nitrogen gas  = 28 g/mole

M_2 = molar mass of sulfur dioxide gas = 64 g/mole

Now put all the given values in the above formula 1, we get:

(\frac{79mL/s}{R_2})=\sqrt{\frac{64g/mole}{28g/mole}}

R_2=52mL/s

Therefore, the rate of effusion of sulfur dioxide gas is 52 mL/s.

4 0
3 years ago
What is meant by the negative sign in an answer like"-46.8kJ"? When would you use a positive sign
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3 years ago
Under certain conditions the rate of this reaction is zero order in dinitrogen monoxide with a rate constant of 0.0067·Ms−1: 2N2
choli [55]

Answer:

5.6 seconds

Explanation:

The reaction follows a zero-order in dinitrogen monoxide

Rate = k[N20]^0 = change in concentration/time

[N20]^0 = 1

Time = change in concentration of N2O/k

Initial number of moles of N2O = 300 mmol = 300/1000 = 0.3 mol

Initial concentration = moles/volume = 0.3/4 = 0.075

Number of moles after t seconds = 150 mmol = 150/1000 = 0.15 mol

Concentration after t seconds = 0.15/4 = 0.0375 M

Change in concentration of N2O = 0.075 - 0.0375 = 0.0375 M

k = 0.0067 M/s

Time = 0.0375/0.0067 = 5.6 s

4 0
3 years ago
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