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PSYCHO15rus [73]
2 years ago
5

Atoms of elements in the same group have the same number of

Chemistry
2 answers:
kherson [118]2 years ago
7 0

Answer:

electrons (can i have brainliest)

Explanation:

Veseljchak [2.6K]2 years ago
3 0

Answer:

Valence Electrons is the correct answer (C)

Explanation:

did the assignment hope this helps

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Fill in the blank: After a chemical reaction, the atoms of the reactant _____ to form new products.
Wewaii [24]
The atoms of the reactant rearrange to form new products.
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3 years ago
Perform the following mathematical operation and then report the answer.
Kisachek [45]
The answer would be 833.7
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3 years ago
How is it possible for there to be more than one kind of atom of the same element?
tiny-mole [99]

They are called isotopes.

Isotopes have the same number of electrons and protons in their unionized state. They differ in the number of neutrons. The first and simplest example is hydrogen.


The most common hydrogen has

1 proton

1 electron and

0 neutrons


It has 2 cousins

1 proton

1 electron

1 neutron

And

1 proton

1 electron

2 neutrons.


Most elements have some differences in the number of neutrons present in their nuclei. Cesium and Xenon have the most number of isotopes. Each has 36. You wonder how the atoms are held together.


6 0
3 years ago
Read 2 more answers
What physical properties can be used to separate heterogeneous mixture's?
marysya [2.9K]
Evaporation, distillation, filtration and chromatography
Hope it help you, have a nice day
7 0
2 years ago
If 3.31 moles of argon gas occupies a volume of 100 L what volume does 13.15 moles of argon occupy under the same temperature an
kumpel [21]

Answer:

397 L

Explanation:

Recall the ideal gas law:

\displaystyle PV = nRT

If temperature and pressure stays constant, we can rearrange all constant variables onto one side of the equation:

\displaystyle \frac{P}{RT} = \frac{n}{V}

The left-hand side is simply some constant. Hence, we can write that:

\displaystyle \frac{n_1}{V_1} = \frac{n_2}{V_2}

Substitute in known values:

\displaystyle \frac{(3.31 \text{ mol})}{(100 \text{ L})}  = \frac{(13.15\text{ mol })}{V_2}

Solving for <em>V</em>₂ yields:

\displaystyle V_2 = \frac{(100 \text{ L})(13.15)}{3.31} = 397 \text{ L}

In conclusion, 13.15 moles of argon will occupy 397* L under the same temperature and pressure.

(Assuming 100 L has three significant figures.)

3 0
2 years ago
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