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Sonja [21]
3 years ago
12

Let v be the vector from initial point Upper P 1P1 to terminal point Upper P 2P2. Write v in terms of i and j. Upper P 1P1equals

=​(negative 8−8​,44​), Upper P 2P2equals=​(66​,44​)
Mathematics
1 answer:
Anna007 [38]3 years ago
3 0

Answer:

The expression of \vec v in terms of i and j is:

\vec v = 74\cdot i + 0\cdot j

Step-by-step explanation:

Let \vec P_{1} and \vec P_{2} vectors with respect to origin, so that \vec P_{1} = (-8,44) and \vec P_{2} = (66,44). \vec v is a vector of the form:

\vec v = \vec P_{2} - \vec P_{1}

Then,

\vec v = (66,44)-(-8,44)

\vec v = (66 + 8, 44 - 44)

\vec v = (74, 0)

The expression of \vec v in terms of i and j is:

\vec v = 74\cdot i + 0\cdot j

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6 0
2 years ago
-5x+y+-2<br> -3x+6y= -12<br><br> solve for x and y
shtirl [24]

Step-by-step explanation:

y+6y-2= -12

7y-2 = -12-2

7y. = -14

7y/7y = -14/7y

y = -2

-5x+-3x

-8x-2-2= -12

-8x -4= -12-4

-8x = -16

-8x/-8x = -16/-8x

x = -2

7 0
3 years ago
I need help with this question
ad-work [718]
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4 years ago
What's 23 x 5/8 I need help
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14 3/8
Hope that helps you!
3 0
3 years ago
Read 2 more answers
A soccer ball is kicked into the air from the ground. If the ball reaches a maximum height of 25 ft and spends a total of 2.5 s
OLga [1]
Hello,

g=9.81m/s²= 9.81/0.3048 =32.18.. ft/s² rounded to 32

h=-g/2*t²+vt+h0
if t=0,h=0 ==>h0=0

==>h=-16*t²+vt
50 ft in 2.5s ==> 25 ft in 1.25s

25=-16*1.25²+v*1.25
==>v=50/1.25=40

Equation h=-16t²+40*t


4 0
3 years ago
Read 2 more answers
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