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Sonja [21]
3 years ago
12

Let v be the vector from initial point Upper P 1P1 to terminal point Upper P 2P2. Write v in terms of i and j. Upper P 1P1equals

=​(negative 8−8​,44​), Upper P 2P2equals=​(66​,44​)
Mathematics
1 answer:
Anna007 [38]3 years ago
3 0

Answer:

The expression of \vec v in terms of i and j is:

\vec v = 74\cdot i + 0\cdot j

Step-by-step explanation:

Let \vec P_{1} and \vec P_{2} vectors with respect to origin, so that \vec P_{1} = (-8,44) and \vec P_{2} = (66,44). \vec v is a vector of the form:

\vec v = \vec P_{2} - \vec P_{1}

Then,

\vec v = (66,44)-(-8,44)

\vec v = (66 + 8, 44 - 44)

\vec v = (74, 0)

The expression of \vec v in terms of i and j is:

\vec v = 74\cdot i + 0\cdot j

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Answer:

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Step-by-step explanation:

The diagram interpreting the question has been attached to this response.

As shown in the diagram,

i. the airplanes leave at point C.

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iii. the points A, B and C form a triangle with sides a, b and c.

To solve for the value of c which is the distance between the two planes at 2.00pm, the cosine rule is used.

c² = a² + b² - 2abcosC            --------------(i)

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Substitute these values into equation (i) and solve as follows;

c² = (487)² + (312)² - 2(312)(487)cos(42)

c² = (237169) + (97344) - 303888cos(42)

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c² = 108693.8272

<em>Take the square root of both sides</em>

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c = 329.69

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