Question

A rubber band has potential energy of 5 J. If the spring constant of the rubber band is 50 N/m, what is the displacement of the rubber band?
0.2 m
1.2 m
0.4 m
0.8 m

Answer 1

The answer is C. 0.4m

Answer 2

Answer:

Explanation:

The elastic potential energy stored in a sprig is given by

$U = \frac{1}{2}Kx^{2}$

Where, K is the spring constant and x be the displacement.

Substitute, K = 50 N/m and U = 5 J

$5 = \frac{1}{2}\times 50\times x^{2}$

By solving, we get

x = 0.44 m = 0.4 m0.4 m