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Sholpan [36]
3 years ago
7

What are the components of Vector B in the diagram provided?

Physics
2 answers:
Vera_Pavlovna [14]3 years ago
8 0

Answer: {C} x=15 m right; y=19.9

Bezzdna [24]3 years ago
7 0
X = 15m right
Y= 19.9
I’d say C or the third one
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A constant current I circulates counterclockwise around a wire loop in the shape of a triangle, lying in x-y plane, with vertice
Blizzard [7]

Answer:

Considering a triangle like the one of the figures, you can obtain the total magnetic force applied on it like the addition of the forces applied to each of the 3 sides.

Been the magnetic force formula:

F=\int\limits^a_b {I} \, \overline {dx} \times \overline {B}

For each segment:

Segment 1 (from [0,0,0] to [a,0,0]):

F=\int\limits^a_0 {I} \, \overline {x}dx \times B \overline {z}=-IBa\overline {y}

Segment 2 (from [a,0,0] to [0,a,0]):

F=\int\limits^{(0,a)}_{(a,0)} {I} \, \frac{\sqrt{2} }{2} (\overline {x}+\overline {y})dx \times B \overline {z}=IB2a(\overline {x}+\overline {y})

Segment 3 (From [0,a,0] to [0,0,0]):

F=\int\limits^0_a {I} \, \overline {y}dx \times B \overline {z}=-IBa\overline {x}

Total force on the wire loop:

F_{T} =F_{1} +F_{2} +F_{3} =-IBa\overline {y}+IB2a(\overline {x}+\overline {y})-IBa\overline {x}=0N

5 0
3 years ago
Devonte pushes a wheelbarrow with 830 W of power. How much work is required to get the wheelbarrow across the yard in 11 s? Roun
zaharov [31]
9,100 is the answer if you do the work so i failed for yall you welcome
8 0
3 years ago
Read 2 more answers
Estimate the mass of the Great Pyramid of Giza, in tons. You make may use of the following information: the Great Pyramid is in
postnew [5]

Answer:

6005803.83105 short tons

Explanation:

The definition of density is \rho = \frac{m}{V}, and the volume of a pyramid is (confusingly written on the proposal) V=\frac{1}{3} Ah, so we can write:

m=\rho V=\rho V \frac{1}{3} Ah=\rho V \frac{1}{3} s^2h

Where s is the side of the base, being s^2 the area of that square.

We will write everything in S.I., and the best way to convert units is using conversion factors, for example, since 1m=100cm, we know that \frac{1m}{100cm}=1, and we can use this factor to convert anything written in cm to anything written in m. Example:

500cm=500cm\frac{1m}{100cm}=5m

Here we just multiplied 500cm by something that is equal to 1 (as every conversion factor must), so <em>it's not doing anything but changing the units</em>.

We can use this tool like this:

2.1\frac{g}{cm^3}=2.1\frac{g}{cm^3}(\frac{1Kg}{1000g})(\frac{100cm}{1m})^3=2100Kg/m^3

Where we have used the fact that 1^3=1 (<u>we can elevate any conversion factor to any number and they still will be 1</u>) and where we have placed strategically what is the numerator and what in the denominator so the units we don't want cancel out and the units we want appear.

Substituting then our values:

m=\rho V \frac{1}{3} s^2h=(2100Kg/m^3)\frac{1}{3} (230.34m)^2(146.7m)=5448373586.96Kg

And now we will convert to short tons using two conversion factors at the same time:

m=5448373586.96\ Kg(\frac{1\ lb}{0.45359237\ Kg})(\frac{1\ short\ ton}{2000\ lb} )=6005803.83105\ short \ tons

Remember, their value is 1, and we place the units to cancel the ones we don't want and keep the ones we want, here Kg cancel out, and lb cancel out, leaving the short tones.

8 0
3 years ago
A car traveled 112.0m in 24.500s, what was a car’s average speed?
kodGreya [7K]

Average speed of the car is 4.57 m/s

Explanation:

  • Speed is calculated by the rate of change of displacement.
  • It is given by the formula, Speed = Distance/Time
  • Here, distance = 112 m and time = 24.5 s

Speed of the car = 112/24.5 = 4.57 m/s

3 0
4 years ago
Friends Burt and Ernie stand at opposite ends of a uniform log that is floating in a lake. The log is 3.0 m long and has mass 20
Taya2010 [7]

Answer:

The distance the log has moved by the time Ernie reaches Bur is 1.33 m.

Explanation:

give information:

The log is 3.0 m long and has mass 20.0 kg.

Burt has mass 30.0 kg; Ernie has mass 40.0 kg

Ernie has mass 40.0 kg.

to find the distance, first, we have to calculate the center of mass

X = ∑ m x /∑m

   = (20 x (3/2)) + (30 x 0) + (40 x 3)/ (20+30+40)

   = 150/90

   = 5/3

when Ernie walk, the center of the mass is

X = (70 x 0) + (20 x (3/2))/(70 + 20)

  = 30/90

  = 1/3

the distance of log moved = 5/3 - 4/3 = 1.33 m

5 0
3 years ago
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