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sertanlavr [38]
3 years ago
14

Which equation is used to calculate the electric potential in an electric field from a point charge? V = kq over d squared V = k

q over d V =delta U over q V = delta U over E
Physics
2 answers:
Contact [7]3 years ago
4 0

Answer:

The answer is V =delta U over q

Explanation:

Electric potential is defined as the magnitude of the electric field through the potential energy that a charge would have if placed at that point. Mathematically, the potential is defined with the following expression:

V=\frac{E_{p} }{q}

where:

V is the electric potential. Its unit is Julius by Coulomb (J/C).

Ep is the electric potential energy that has a charge

q is the charge

In the question Ep = ΔU

Oduvanchick [21]3 years ago
4 0

Answer:

The answer is V=kq/d

Explanation:

The electrostatic potential is defined in terms of work done in taking a unit positive charge from infinity to the point in question.

V=kq/d

Where d= distance from infinity to the point in question

k= constant of proportionality

q= attracting charge

The electric potential is measured in volts

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8. A 40.0kg block of metal is suspended from a scale and is immersed in water. The dimensions of the block are 12.0cm x 10.0cm x
Alja [10]

Answer:

a.1017.9N

b.1029.7N

c.T=380.6N

d.11.8 N

Explanation:

(a) The absolute pressure at the level of the top of the block is

Po=atmospheric pressure

g=gravity

h1=height

rh0=density of water

P1=Po+rho*g*h1

1.013*10^5+1000(9.81)(0.05)

1.0179*10^5Pa

at the level of the bottom of the block we have

P2=Po+rho*g*h2

1.013*10^5+1000(9.81)(0.17)

1.0297* 10^5 Pa

the downward force exerted on the top by the water is

Ftop=P*A== × = 1.0179* 10^5* 0.100

= 1017.9 N

and the upward force the water exerts on the bottom of the block , which is the buoyant force

Fbot== × = 1.0297 10^5 * 0.100 m

= 1029.7 N

(b) The scale reading is the tension, T, in the cord supporting the block.

if the block is at equilibrium, then sum of vertical forces

EFy=T+Fbot-Ftop-mg=0

T=mg+Ftop-Fbot

T=40*9.81-(1029.7-1017.9)

T=380.6N

(c)  Archimedes principle state that, the buoyant force on the block equals the weight of the displaced water. Thus,

Buoyant force=rho *g*h

= = 1000* 0.100^2 * 0.120 m *9.80 m s=11.8 N

from the answer a Ftop-Fbot

1029.7-1017.9=11.8N, the same as the buoyant force

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3 years ago
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