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Andru [333]
4 years ago
7

John’s mass is 93.3 kg, and Barbara’s is 50.1 kg. He is standing on the x axis at xJ = +9.03 m, while she is standing on the x a

xis at xB = +3.36 m. They switch positions. How far and in which direction does their center of mass move as a result of the switch? Distance m
Physics
1 answer:
Aleks [24]4 years ago
7 0

Answer:

\Delta r=-1.71m  It moves 1.71m to the left.

Explanation:

The intial position of the center of mass is:

ro = \frac{m_J*r_J+m_B*r_B}{m_J+m_B} =7.05m

The final position of the center of mass is:

rf = \frac{m_J*r_B+m_B*r_J}{m_J+m_B} =5.34m

The displacement between these positions is:

Δr = 5.34m - 7.05m = -1.71m

This means it moves 1.71m to the negative x-axis

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A bowler throws a bowling ball of radius R = 11 cm along a lane. The ball slides on the lane with initial speed <img src="https:
s344n2d4d5 [400]

Answer:

a) v_com= Rω

b) -2.254 m/s^{2}

c) 51.2 rad/s^{2}

d) t=1.08 seconds

e) x=7.865m

f) v_roll=6.07m

Explanation:

Initially, the ball is travelling with v_com=v_0

Wen not rotating, at the initial stage the ball must be sliding along the surface.

This motion therefore generates a frictional force F_r at the point of contact.

Let the velocity at the point of contact be v_bottom

v_bottom=v_com-Rω

Therefore when ω=0, v_bottom=v_com

So when the ball begins rolling

v_com= Rω

F_r=μ_rmg

〖-F〗_r=ma_com

a_com=(〖-μ〗_r mg)/m

a_com=-μ_rg

a_com=-(0.23)(9.8)

a_com=-2.254m/s^2

Te negative sow decrearse  

\alpha=(μ_r mgR)/I  =  (〖5μ〗_r mgR)/2mRR

=(〖5μ〗_r g)/2R

=(5*(0.23)*(9.8))/(2*0.11)

=51.2 rad/s^2

t=v_0/(〖-a〗_com+Rα)

=8.5/(2.255+0.11*(51.2))

=8.5/7.886

=1.08 seconds

X=v_0 t+1/2 a_com t^2

X=8.5*(2.254) -  1/2 (2.254)*〖1.08〗^2

=7.865m

v_roll=v_0+a_com t_r

=8.5-(2.254)(1.08)

        =6.07m/sec

Initially, the ball is travelling with v_com=v_0

Wen not rotating, at the initial stage the ball must be sliding along the surface.

This motion therefore generates a frictional force F_r at the point of contact.

a) Let the velocity at the point of contact be v_bottom

v_bottom=v_com-Rω

Therefore when ω=0, v_bottom=v_com

So when the ball begins rolling

v_com= Rω

b)    F_r=μ_rmg

〖-F〗_r=ma_com

a_com=(〖-μ〗_r mg)/m

a_com=-μ_rg

a_com=-(0.23)(9.8)

a_com=-2.254m/s^2

Te negative sow decrearse  

c) α=(μ_r mgR)/I  =  (〖5μ〗_r mgR)/2mRR

=(〖5μ〗_r g)/2R

=(5*(0.23)*(9.8))/(2*0.11)

=51.2 rad/s^2

d) t=v_0/(〖-a〗_com+Rα)

=8.5/(2.255+0.11*(51.2))

=8.5/7.886

=1.08 seconds

e) X=v_0 t+1/2 a_com t^2

X=8.5*(2.254) -  1/2 (2.254)*〖1.08〗^2

=7.865m

f) v_roll=v_0+a_com t_r

=8.5-(2.254)(1.08)

        =6.07m/sec

7 0
4 years ago
Does any body know anything about Criminal justice??
Natasha_Volkova [10]

Criminal justice is the delivery of justice to those who have committed crimes. The criminal justice system is a series of government agencies and institutions whose goal is to identify and catch the law-breakers and to inflict a form of punishment on them.


-Hope this Helps

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Answer:

Its ahhshshgd

Explanation:

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An object with a mass of 2 kilograms is accelerated at 5 m/s2.
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Answer:

It would be 40

Explanation:

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Which shared property belongs in the region marked "B"?
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