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Nonamiya [84]
3 years ago
14

Will mark brainliest and give 20 points! In what ways can vertical, horizontal, and oblique asymptotes be identified? Please use

your own example to identify.

Mathematics
1 answer:
Reil [10]3 years ago
3 0
Vertical asymptote:
When you have a rational expression in which the denominator is zero, you have a vertical asymptote. So to find vertical asymptotes, just set the denominator of your rational expression equal to zero, and then, solve for x:
\frac{x-1}{x-3}
Set the denominator equal to zero:
x-3=0
Solve for x:
x=3 is the vertical asymptote of our rational expression.

Horizontal asymptote:
Here we have two scenarios.
1) Is the degree of the denominator is higher than the degree of the numerator, you will have a horizontal asymptote at y=0:
y= \frac{x-1}{x^{2}+3}
Since the degree of the denominator is higher of the degree of the numerator, our rational expression will have an asymptote at y=0
2) If the degree of both denominator and numerator is the same, the rational expression will have an horizontal asymptote at the ratio of the leading coefficients:
\frac{3x^{2}+5}{2x^2-3x+1}
Leading coefficients: 3 and 2
Ratio of leading coefficients:
\frac{3}{2}. Our rational expression will have an horizontal asymptote at y= \frac{3}{2}

Oblique asymptote:
If the degree of the numerator is higher than the degree of the numerator, you will have an oblique asymptote. To find it, we are going to perform long division; the quotient (without the remainder) will be the equation of the oblique asymptote line:
\frac{x^2+5x+2}{x+1}
The quotient of the long division is x-1 with a remainder of 2; therefore, the equation of the oblique asymptote line will be:
y=x+4

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kolbaska11 [484]

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<h3>How much would a shipment of 2560 tennis balls weigh?</h3>

We know that 24 tennis balls weigh 3 pounds. Then the weight of a single tennis ball is:

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