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Nonamiya [84]
3 years ago
14

Will mark brainliest and give 20 points! In what ways can vertical, horizontal, and oblique asymptotes be identified? Please use

your own example to identify.

Mathematics
1 answer:
Reil [10]3 years ago
3 0
Vertical asymptote:
When you have a rational expression in which the denominator is zero, you have a vertical asymptote. So to find vertical asymptotes, just set the denominator of your rational expression equal to zero, and then, solve for x:
\frac{x-1}{x-3}
Set the denominator equal to zero:
x-3=0
Solve for x:
x=3 is the vertical asymptote of our rational expression.

Horizontal asymptote:
Here we have two scenarios.
1) Is the degree of the denominator is higher than the degree of the numerator, you will have a horizontal asymptote at y=0:
y= \frac{x-1}{x^{2}+3}
Since the degree of the denominator is higher of the degree of the numerator, our rational expression will have an asymptote at y=0
2) If the degree of both denominator and numerator is the same, the rational expression will have an horizontal asymptote at the ratio of the leading coefficients:
\frac{3x^{2}+5}{2x^2-3x+1}
Leading coefficients: 3 and 2
Ratio of leading coefficients:
\frac{3}{2}. Our rational expression will have an horizontal asymptote at y= \frac{3}{2}

Oblique asymptote:
If the degree of the numerator is higher than the degree of the numerator, you will have an oblique asymptote. To find it, we are going to perform long division; the quotient (without the remainder) will be the equation of the oblique asymptote line:
\frac{x^2+5x+2}{x+1}
The quotient of the long division is x-1 with a remainder of 2; therefore, the equation of the oblique asymptote line will be:
y=x+4

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i jave a 5 in my ones place. the digit in my tens place os 3 plus the digit in my ones place. the digit in my hundreds place is
KatRina [158]

Answer:

The number is 385.

Step-by-step explanation:

The 5 is in the ones place so you put that at the end. The digit in the tens place is 3 plus the digit in the ones place which is 5 so 3 + 5 = 8 so the 8 is in the tens place. The digit in the hundreds place is 2 less than the digit in the ones place which is 5 so 5 - 2 = 3 so the 3 is in the hundreds place

4 0
3 years ago
H(x) = −(x − 5)2 + 3
aleksandr82 [10.1K]
Max(f(x)) = f(3) = 4

Max(g(x)) = g(π/2) = 2

Max(h(x)) = h(5) = 3

Of these values, f(3) = 4 is the largest.


The function with the largest maximum is f(x).
8 0
3 years ago
Read 2 more answers
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Vilka [71]
I'd honestly go with forty eight.
5 0
4 years ago
13 - 2(1 - 15) ÷ 4. Can anyone help me do my homework <br><br> Please help me
Ilia_Sergeevich [38]

Remember to follow PEMDAS.

First, solve the parenthesis.

(1 - 15) = -14

13 - 2(-14) ÷ 4

Next, multiply -2 and -14 (remember to bring the signs.

-2 x -14 = 28

13 + 28/4

Next, divide

28/4 = 7

13 + 7

Finally, subtract

13 + 7 = 20

20 is your answer

hope this helps

4 0
3 years ago
Unit test Select two ratios that are equivalent to 2 : 12. Choose 2 answers: A 6:40 B 12:2 C 3:24 D 1:6 E 8:48​
Sophie [7]
D & E

D) if you divide the ratios by 2 you get 1:6
E) if you multiply each ratio by 4 you get 8:48

You can’t divide or multiply any of the other numbers with 2 and 12 (together) to get you the other answers
6 0
3 years ago
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