So,
Let's calm down and translate this word problem.
The 8-ct. pack costs 0.03 cents more per bun than the 10-ct. pack.
x = cost of 8-ct. pack
y = cost of 10-ct. pack
We now have the equation:

Also, we are told that the 8-ct. pack is 0.45 cents less than the 10-ct. pack.
x = y - 0.45 cents
With these two equations, we can now solve for x and y.
First, substitute y - 0.45 cents for x in the first equation.

Multiply both sides by 80 and simplify.
10(y - 0.45 cents) = 8y + 2.40 cents
10y - 4.50 cents = 8y + 2.40 cents
Subtract 8y from both sides and add 4.50 cents to both sides.
2y - 4.50 cents = 2.40 cents
2y = 6.90 cents
Divide both sides by 2.
y = 3.45 cents
Substitute 3.45 cents for y in the second equation.
x = 3.45 cents - 0.45 cents
x = 3.00 cents
The 8-ct. pack costs 3.00 cents, and the 10-ct. pack costs 3.45 cents.