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Leto [7]
3 years ago
7

Mirrors on cars exist to____.

Computers and Technology
2 answers:
TEA [102]3 years ago
7 0

Answer:

c is ur answer

Explanation:

Drupady [299]3 years ago
4 0

Answer:

C. Minimize blind spots

Explanation:

The mirrors are to let you see in places that you would not be able to see without turning around (aka. blind spots).

Hope this helps :)

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What is the biggest difference between a movie and a game?
sveta [45]

Answer:

It could be D

Explanation:

3 0
2 years ago
Determine the output of the following code segment:
Nataly [62]

Answer:

The output to the given code as follows:

Output:

10

100

64

36

16

4

0

4

16

36

64

Explanation:

In the given java code, an integer variable "i" and an array number is defined, which size is 10, in the next step two for loop is declared, that can be described as follows:

  • In the first loop, array use loop variable "i" use, which minus the value of 5 and multiplies by 2, and it will calculate the square of that number.
  • In the next step, a for loop is declared, that prints these array number variable square.
7 0
3 years ago
Attacking systems by exploiting otherwise unknown and unpatched vulnerabilities is also known as:
Nostrana [21]

Answer:

Zero-day exploits

Explanation:

Zero-day exploits refers to recently found vulnerabilities in a computer software program that has been in existence but was hitherto not known and addressed by the software security experts, however, these vulnerabilities were known to hackers. While the existence of these "loop-holes" in the software can go on unnoticed for several years, hackers can take advantage of it to cause harm to the computers' programs and data.

When these attacks occur, it is called a zero-day because the attack took place on the very day that the loop-hole was discovered in the software. So exploitation has already taken place before a fix is carried out.

5 0
3 years ago
In Coral programming: A half-life is the amount of time it takes for a substance or entity to fall to half its original value. C
viva [34]

Answer:

Yes, it will be after 6 hours: 50 mg, after 12 hours: 25 mg, and after 18 hours: 12.5 mg

Explanation:

Remember coral is a functional programming language and follows Pythons functional programming paradigm. Remember Python supports functional, imperative as well as OOPS paradigm.

The function will be:

def void calcamtleft(int amt):

   integer a=6

   integer time=6

   integer i=1

   while amt> 0:

       amt=amt/2

       print("After"+time+"  hours:" +amt+"mg")

       i++

       time=a* i

Hence in first loop amt=100

new amt=100/2=50

After 6 hours: 50 mg ( this will be printed)

i will increment then, and time will be = 6 *2 =12

now input amt=50

new amt=50/2=25

After 12 hours 25 mg (this will be output)

i will increment then, and time will be = 6 *3 =18

now input amt=25

new amt=25/2=12.5

After 18 hours 12.5 mg (this will be output)

i will increment then, and time will be = 6 *4 =24

now input amt=12.5/2= 6.25

new amt=6.25/2= 3.125

After 24 hours 3.125 mg (this will be output)

i will increment then, and time will be = 6 *5 =30

now input amt=3.125

new amt=3.125/2= 1.5625

After 30 hours 1.5625 mg

And this will continue till amt>0

7 0
3 years ago
Create a program that displays a menu to select addition, subtraction, or multiplication. Using random numbers between 0 and 12
Lemur [1.5K]

Answer:

This question is answered using C++

#include<iostream>

#include <cstdlib>

#include <ctime>

using namespace std;

int main(){

   int ope, yourresult;

   cout<<"Select Operator: \n"<<"1 for addition\n"<<"2 for subtraction\n"<<"3 for multiplication\n";

   cout<<"Operator: ";

   cin>>ope;

   srand((unsigned) time(0));

   int num1 = rand() % 12;

   int num2 = rand() % 12;

   int result = 1;

   if(ope == 1){

       cout<<num1<<" + "<<num2<<" = ";

       result = num1 + num2;

   }

   else if(ope == 2){

       cout<<num1<<" - "<<num2<<" = ";

       result = num1 - num2;

   }

   else if(ope == 3){

       cout<<num1<<" * "<<num2<<" = ";

       result = num1 * num2;

   }

   else{

       cout<<"Invalid Operator";

   }

   cin>>yourresult;

   if(yourresult == result){

       cout<<"Correct!";

   }

   else{

       cout<<"Incorrect!";

   }

   return 0;

}

Explanation:

This line declares operator (ope) and user result (yourresult) as integer

   int ope, yourresult;

This prints the menu

   cout<<"Select Operator: \n"<<"1 for addition\n"<<"2 for subtraction\n"<<"3 for multiplication\n";

This prompts the user for operator

   cout<<"Operator: ";

This gets user input for operator

   cin>>ope;

This lets the program generates different random numbers

   srand((unsigned) time(0));

This generates the first random number

   int num1 = rand() % 12;

This generates the second random number

   int num2 = rand() % 12;

This initializes result to 1

   int result = 1;

If the operator selected is 1 (i.e. addition), this prints an addition operation and calculates the actual result

<em>    if(ope == 1){</em>

<em>        cout<<num1<<" + "<<num2<<" = ";</em>

<em>        result = num1 + num2;</em>

<em>    }</em>

If the operator selected is 2 (i.e. subtraction), this prints an subtracttion operation and calculates the actual result

<em>    else if(ope == 2){</em>

<em>        cout<<num1<<" - "<<num2<<" = ";</em>

<em>        result = num1 - num2;</em>

<em>    }</em>

If the operator selected is 3 (i.e. multiplication), this prints an multiplication operation and calculates the actual result

<em>    else if(ope == 3){</em>

<em>        cout<<num1<<" * "<<num2<<" = ";</em>

<em>        result = num1 * num2;</em>

<em>    }</em>

If selected operator is not 1, 2 or 3, the program prints an invalid operator selector

<em>    else{</em>

<em>        cout<<"Invalid Operator";</em>

<em>    }</em>

This gets user input

   cin>>yourresult;

This checks if user result is correct and prints "Correct!"

   if(yourresult == result){

       cout<<"Correct!";

   }

If otherwise, the program prints "Incorrect!"

<em>    else{</em>

<em>        cout<<"Incorrect!";</em>

<em>    }</em>

   return 0;

6 0
3 years ago
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