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3 years ago

Which choice is not an example of a molecule Mn O3 KOH H2S

Chemistry

2 answers:

kompoz [17]3 years ago

8 0

Answer: Mn

Explanation: Hope this helps -Amy <3

Vlad [161]3 years ago

3 0

Answer:

The correct answer is Mn

Explanation:

I hope you get the question right because I did!

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Chromium(III) oxide can be prepared by heating chromium(IV) oxide in vacuo at high temperature: 4Cr02 —2Cr2O3 +02 The reaction o

kkurt [141]

<u>Answer:</u> The theoretical yield and percent yield of chromium (III) oxide is 434.72 grams and 92.6 % respectively.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of $CrO_2$ = 480.1 g

Molar mass of $CrO_2$ = 84 g/mol

Putting values in equation 1, we get:

$\text{Moles of }CrO_2=\frac{480.1g}{84g/mol}=5.72mol$

For the given chemical equation:

$4CrO_2\rightarrow 2Cr_2O_3+O_2$

By Stoichiometry of the reaction:

4 moles of $CrO_2$ produces 2 moles of chromium (III) oxide

So, 5.72 moles of $CrO_2$ will produce = $\frac{2}{4}\times 5.72=2.86mol$ of chromium (III) oxide

Now, calculating the mass of chromium (III) oxide from equation 1, we get:

Molar mass of chromium (III) oxide = 152 g/mol

Moles of chromium (III) oxide = 2.86 moles

Putting values in equation 1, we get:

$2.86mol=\frac{\text{Mass of chromium (III) oxide}}{152g/mol}\\\\\text{Mass of chromium (III) oxide}=(2.86mol\times 152g/mol)=434.72g$

To calculate the percentage yield of chromium (III) oxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of chromium (III) oxide = 402.4 g

Theoretical yield of chromium (III) oxide = 434.72 g

Putting values in above equation, we get:

$\%\text{ yield of chromium (III) oxide}=\frac{402.4g}{434.72g}\times 100\\\\\% \text{yield of chromium (III) oxide}=\%$

Hence, the theoretical yield and percent yield of chromium (III) oxide is 434.72 grams and 92.6 % respectively.

7 0

3 years ago

if atoms of lithium and sodium easily give up a single electron which other elements also have this property

Mars2501 [29]

Basically all of the elements found in Group I of the periodic table also have this property. The ability to easily give up a single valence electron.

6 0

3 years ago

A concentrated salt solution has a mass of 5.222 g for a 5.000 mL sample.

ad-work [718]

The specific gravity or relative density of a substance is the ratio of its density to the density of a reference material. The relative density of the concentrated salt solution is 1.044.

Mathematically;

Density of the concentrated salt = mass of salt/volume of salt = 5.222 g/5.000 mL = 1.044 g/mL

In the case of specific gravity, the reference material is always water and water has a density of 1 g/mL.

Hence, specific gravity of the concentrated salt solution =

Density of concentrated salt solution/density of equal volume of water

= 1.044 g/mL/1 g/mL

= 1.044

Note that specific gravity is dimensionless.

Learn more: brainly.com/question/9638888

6 0

2 years ago

Does the color of bell peppers effect the number of seeds inside? Please someone help ASAP I need it today

Mekhanik [1.2K]

I don't think so. "It's not a matter of pigment discrimination: Red and yellow bell peppers are essentially just green peppers that have been allowed to ripen"

3 0

2 years ago

hat is the pH of a solution with a hydroxide ion concentration of 10–6M? A. pH = 12 B. pH = 8 C. pH = 6 D. pH = 7

WARRIOR [948]

C=10⁻⁶ mol/L

pH=14-pOH

pOH=-lg[OH⁻]

pH=14+lg10⁻⁶=14-6=8

B. pH = 8

8 0

3 years ago