Which is larger, 51.5 decigrams or 51,500 decigrams

The surface of water can act like a sort of skin due to a property of liquids called

stiv31 [10]

Surface tension ..viscosity is the thickness of a liquid, doesn't fit here...condensation and evaporation are processes not properties.

8 0

3 years ago

Read 2 more answers

Which of the following best describes earth tectonic plates ?

meriva

Answer:

B They move because of the convection currents in the mantle.

6 0

2 years ago

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How much heat must your body transfer to 500.0g of water to heat it from 25.0°C to body temperature, 37.0°C?

shtirl [24]

Answer : The heat your body transfer must be, 25.1 kJ

Explanation :

Formula used :

$Q=m\times c\times \Delta T$

or,

$Q=m\times c\times (T_2-T_1)$

where,

Q = heat = ?

m = mass of water = 500.0 g

c = specific heat of water = $4.18J/g^oC$

$T_1$ = initial temperature = $25.0^oC$

$T_2$ = final temperature = $37.0^oC$

Now put all the given value in the above formula, we get:

$Q=500.0g\times 4.18J/g^oC\times (37.0-25.0)K$

$Q=25080J=25.1kJ$

Therefore, the heat your body transfer must be, 25.1 kJ

3 0

3 years ago

HOW TO DO STOICHIOMETRY

stellarik [79]

Answer:

1.Balance the equation.

2.Convert units of a given substance to moles.

3.Using the mole ratio, calculate the moles of substance yielded by the reaction.

4.Convert moles of wanted substance to desired units.

Explanation:

8 0

3 years ago

Water vapor enters a compressor at 35 kpa and 160°c and leaves at 300 kpa with the same specific entropy as at the inlet. What a

Annette [7]

<h3>solution:</h3>

The initial entropy is obtained from the initial pressure and temperature with data from A-6 using interpolation:

s= 8.2652 kJ/kgK

The final temperature is determined from the entropy and the final pressure with data from A-6 using interpolation:

T₂ = T₁+ T₂ - T₁/ 8₂ - 8₁ ( s - s₁)

= (400 + 500 - 400/8.3271 - 8.0347 (8.2652 - 8))

= 478.83°C

The final enthalpy is determined in the same way:

h₂= h₁ + h₂ - h₁/s₂ - s₁ ( s - s₁)

= ( 3275.5+ 3486.6 - 3275.5/ 8.3271 - 8.0347) (8.265)

= 3441.91 kJ/kg

6 0

2 years ago