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luda_lava [24]
3 years ago
7

Calculate molality of a 2m aq solution of sodium chloride with density 1.35g/mol

Chemistry
1 answer:
swat323 years ago
5 0
There are a number of ways to express concentration of a solution. This includes molarity and molality. Molarity is expressed as the number of moles of solute per volume of the solution while molality is expressed as the number of moles solute per mass of solution. Calculation is as follows:

(2 mol NaCl / L solution) ( 1 cm^3 / 1.35 g) ( 1000 L / 1 cm^3) (1000 g /kg) = 1.5 x 10^6 mol / kg solution
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How many particles of Na are there in 1.43g of a molecular compound with a Molar mass of 23g?
Olin [163]

Answer:

3.74 x 10²² particles

Explanation:

Given parameters:

Mass of compound  = 1.43g

Molar mass of compound  = 23g

Unknown:

Number of particles of sodium = ?

Solution:

To find the number of particles of Na in the compound, we need to obtain the mass of sodium from the total mass given;

          Mass of sodium  = \frac{molar mass of Na}{molar mass of compound} x mass of sample

                                      = \frac{23}{23}  x 1.43g

                                       = 1.43g

Now find the number of moles of this amount of Na in the sample;

          Number of moles  = \frac{mass}{molar mass} = \frac{1.43}{23}  = 0.062mole

Now;

                    1 mole of substance  = 6.02 x 10²³ particles

                       0.062 mole of substance  =  0.062 x 6.02 x 10²³ particles

                                                                     = 3.74 x 10²² particles

7 0
3 years ago
A solution is prepared by dissolving 0.23 mol of lactic acid and 0.27 mol of sodium lactate in water sufficient to yield 1.00 L
PtichkaEL [24]

Explanation:

The solution of the lactic acd and sodium lactate is referred to as a buffer solution.

A buffer solution is an aqueous solution consisting of a mixture of a weak acid and its conjugate base, or vice versa. In this case, the weak acid is the lactic acid and the conjugate base is the sodium lactate.

Buffer solutions are generally known to resist change in pH values.

When a strong base (in this case, NaOH) is added to the buffer, the lactic acid will give up its H+ in order to transform the base (OH-) into water (H2O) and the conjugate base, so we have:

HA + OH- → A- + H2O.

Since the added OH- is consumed by this reaction, the pH will change only slightly.

The NaOH reacts with the weak acid present in the buffer sollution.

6 0
3 years ago
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Is there a way of making your hair grow longer without spending for hair growth?
miv72 [106K]
No technically without buying anything your hair will not grow .
4 0
3 years ago
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A balloon with a volume of 2.0 l at 25°c is placed in a hot room at 35°c. the pressure on the balloon is constant at 1.0 atm. fo
shusha [124]

The volume increases and the final volume is 2.1 L

<h3>Why volume increases?</h3>

The volume of a gas is directly related to the heat and pressure. If temperature increases, volume increases.

If pressure increases, volume decreases

Based on Boyle's law,

The absolute temperature of a gas is directly proportional to the volume of the gas.

As the balloon change increases its temperature, the volume increases

The Boyle's equation is:

V₁T₂ = V₂T₁

Where,

  • V is volume
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Replacing :

V₁ = 2.0L

T₂ = 35°C + 273.15 = 308.15K

V₂ = ?

T₁ = 25°C + 273.15 = 298.15 K

2.0L x 308.15 K = V₂ x 298.15 K

2.1 L = V₂

Final volume is 2.1L

Hence, The volume increases and the final volume is 2.1 L

Learn more about gas laws here ;

brainly.com/question/12669509

#SPJ1

5 0
2 years ago
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The phase that is most likely to occur at high temperatures and high pressures is ??
Tju [1.3M]
The correct answer is D.

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