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luda_lava [24]
3 years ago
7

Calculate molality of a 2m aq solution of sodium chloride with density 1.35g/mol

Chemistry
1 answer:
swat323 years ago
5 0
There are a number of ways to express concentration of a solution. This includes molarity and molality. Molarity is expressed as the number of moles of solute per volume of the solution while molality is expressed as the number of moles solute per mass of solution. Calculation is as follows:

(2 mol NaCl / L solution) ( 1 cm^3 / 1.35 g) ( 1000 L / 1 cm^3) (1000 g /kg) = 1.5 x 10^6 mol / kg solution
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Answer:

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Explanation:

Given parameters:

Mass of NaCl  = 1.4kg  = 1400g

Unknown:

Number of ions of sodium  = ?

Solution:

The compound NaCl in ionic form can be written as;

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In 1 mole of NaCl we have 1 mole of sodium ions

 Now, let us find the number of moles in NaCl;

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    Molar mass of NaCl  = 23 + 35.5 = 58.5g/mol

Number of moles  =  \frac{1400}{58.5}     = 23.93mol

 So;

   Since 1 mole of NaCl gives 1 mole of Na⁺  

    In 23.93 mole of NaCl will give 23.93 mole of Na⁺

1 mole of a substance  = 6.02 x 10²³ ions of a substance

  23.93 mole of a substance  =  6.02 x 10²³ x  23.93

                                                   = 1.44 x 10²⁵ ions of Na⁺

7 0
3 years ago
Analyze how friction can be both a positive and negative aspect in our everyday lives. Use examples to support your statements.
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Answer:

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Explanation:

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Reason: 
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dezoksy [38]
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Answer:

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